2016
DOI: 10.1007/s00440-016-0719-z
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Conditioned limit theorems for products of random matrices

Abstract: Let g 1 , g 2 , . . . be i.i.d. random matrices in G L (d, R) . For any n ≥ 1 consider the product G n = g n . . . g 1 and the random processIt is well known that under appropriate assumptions, the sequence (log G n v ) n≥1 behaves like a sum of i.i.d. r.v.'s and satisfies standard classical properties such as the law of large numbers, the law of iterated logarithm and the central limit theorem. For any vector v with v > 1 denote by τ v the first time when the random process G n v enters the closed unit ball i… Show more

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Cited by 22 publications
(25 citation statements)
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“…The asymptotic behaviour of the probability Px ,a (τ > n) is established in [13] when the matrices M n are invertible and in [21] when the M n has non negative entries, under several conditions P1-P5; the first step is to establish the existence of a P + -harmonic function h on X × R + . Our hypotheses H1, H2, H4 and H5 are exactly P1, P2, P4 and P5 in [21] and H3 is obviously stronger than P3.…”
Section: The Distribution µ Of the Matricesmentioning
confidence: 99%
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“…The asymptotic behaviour of the probability Px ,a (τ > n) is established in [13] when the matrices M n are invertible and in [21] when the M n has non negative entries, under several conditions P1-P5; the first step is to establish the existence of a P + -harmonic function h on X × R + . Our hypotheses H1, H2, H4 and H5 are exactly P1, P2, P4 and P5 in [21] and H3 is obviously stronger than P3.…”
Section: The Distribution µ Of the Matricesmentioning
confidence: 99%
“…where σ 2 > 0 is the variance of the Markov walk (S n ) n≥0 , given in [13]. Moreover, there exists a constant c > 0 such that for anyx ∈ X, a ≥ 0 and…”
Section: The Distribution µ Of the Matricesmentioning
confidence: 99%
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“…Under assumptions of Theorem 1 asymptotics (11) hold with function U g defined in(13) which is slowly varying. Moreover, for all n ≥ 1α * n := B n P(T g > n) EZ * n − 2ϕ(0) ≤ C 1 ρ 2/for some C 1 < ∞.We split the proof into several steps.…”
mentioning
confidence: 98%