2017
DOI: 10.1093/imrn/rnx104
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Conditionally Bi-Free Independence with Amalgamation

Abstract: In this paper, we introduce the notion of conditionally bi-free independence in an amalgamated setting. We define operator-valued conditionally bi-multiplicative pairs of functions and construct operatorvalued conditionally bi-free moment and cumulant functions. It is demonstrated that conditionally bifree independence with amalgamation is equivalent to the vanishing of mixed operator-valued bi-free and conditionally bi-free cumulants. Furthermore, an operator-valued conditionally bi-free partial R-transform i… Show more

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Cited by 7 publications
(18 citation statements)
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“…. , m + n}, we obtain On the other hand, expanding M (Z ℓ ,Zr ) (b, d) using the fact it converges absolutely produces As the cbi-free, operator-valued c-bi-free, and bi-Boolean analogues of these results are available in [11,Section 4], [12,Section 7], and Section 4 above respectively, it can be shown without any difficulty that similar results also hold in the framework of the current section.…”
Section: 2mentioning
confidence: 95%
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“…. , m + n}, we obtain On the other hand, expanding M (Z ℓ ,Zr ) (b, d) using the fact it converges absolutely produces As the cbi-free, operator-valued c-bi-free, and bi-Boolean analogues of these results are available in [11,Section 4], [12,Section 7], and Section 4 above respectively, it can be shown without any difficulty that similar results also hold in the framework of the current section.…”
Section: 2mentioning
confidence: 95%
“…Furthermore, like any other non-commutative probability theory, whenever a notion of independence (scalar-valued or operator-valued) is defined, a number of limit theorems can be obtained for various purposes. Since we do not have any immediate applications of the operator-valued bi-Boolean limit theorems available at the moment, we will simply mention that the bi-Boolean analogues of the operator-valued bi-free/c-bi-free limit theorems in [12,Section 9] can be easily proved by the same techniques.…”
Section: 2mentioning
confidence: 99%
“…Note that Z * bf is of the same type as Z f b following Proposition-Defintion 6.9 (4), (5). It is easy to check that the following relation holds: Ψ(Z bf ) * = Ψ * (Z * bf ).…”
Section: Positivity Of the Amalgamated Free-boolean Productmentioning
confidence: 97%
“…Hence E(Z f bf A) = 0. Similary, BZ f bf can be written as the summation of elemtns of the types (4) and (5). Hence E(BZ f bf ) = 0.…”
Section: Moment-conditions For Free-boolean Independencementioning
confidence: 98%
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