2010
DOI: 10.1007/s10587-010-0027-1
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Components and inductive dimensions of compact spaces

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Cited by 6 publications
(5 citation statements)
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“…We shall recall the definition of the space Z(X, Y ), and investigate its properties (cf. [10]). To begin, write S X for the family of all subsets of X that are either finite (so ∅ ∈ S X ), or homeomorphic to A ℵ 0 .…”
Section: Spreading Out Compact Spaces In a Plankmentioning
confidence: 99%
See 3 more Smart Citations
“…We shall recall the definition of the space Z(X, Y ), and investigate its properties (cf. [10]). To begin, write S X for the family of all subsets of X that are either finite (so ∅ ∈ S X ), or homeomorphic to A ℵ 0 .…”
Section: Spreading Out Compact Spaces In a Plankmentioning
confidence: 99%
“…It follows from Lemma 2.2 that Remark 4.7. The construction in the above proof is essentially the same as in the proof of Theorem 5 in [10] (see Remarks 3-4 therein), which yields a compact Fréchet space X C,α with dim X C,α = n, trind X C,α = trInd X C,α = α, and with components homeomorphic to C. The proofs of Lemmas 4.1 and 4.3 in the present paper are more complex than the proofs of corresponding Lemmas 6 and 7 in [10].…”
Section: Spreading Out Compact Spaces In a Plankmentioning
confidence: 99%
See 2 more Smart Citations
“…For some other maps f : X → Y , even Ind X −Ind f X −Ind f > 1. For every pair of natural numbers m > n ≥ 1, the present author [33] has constructed a compact space X m,n such that Ind X m,n = m and every component of X m,n is homeomorphic to the n-dimensional cube [0, 1] n . In consequence, if D stands for the decomposition of X m,n into its components, and f K : X m,n → X m,n /D is the natural quotient map (it is not fully closed), then Ind X m,n − Ind X m,n /D − Ind f K = m − n.…”
Section: −1mentioning
confidence: 99%