2022
DOI: 10.48550/arxiv.2204.00908
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Complexity and entanglement in non-local computation and holography

Abstract: Does gravity constrain computation?We study this question using the AdS/CFT correspondence, where computation in the presence of gravity can be related to non-gravitational physics in the boundary theory. In AdS/CFT, computations which happen locally in the bulk are implemented in a particular non-local form in the boundary, which in general requires distributed entanglement. In more detail, we recall that for a large class of bulk subregions the area of a surface called the ridge is equal to the mutual inform… Show more

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Cited by 2 publications
(3 citation statements)
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“…In holography, even for n = 2 the boundary protocol is most naturally modeled as an EAQECC: the particles fall into the bulk is the encoding step, then logical operations are performed on the encoded systems in tensor product form, then the systems are decoded, pulling them out from the bulk. Given the tension between the efficiency, in terms of entanglement use, in AdS/CFT vs in existing non-local computation protocols in quantum information [29], it is natural to explore EAQECC based non-local computation protocols in more detail. A simple starting point may be to adapt the code based strategies of [56] to use entanglement-assisted codes.…”
Section: Why No N-to-m Theorem For N = M?mentioning
confidence: 99%
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“…In holography, even for n = 2 the boundary protocol is most naturally modeled as an EAQECC: the particles fall into the bulk is the encoding step, then logical operations are performed on the encoded systems in tensor product form, then the systems are decoded, pulling them out from the bulk. Given the tension between the efficiency, in terms of entanglement use, in AdS/CFT vs in existing non-local computation protocols in quantum information [29], it is natural to explore EAQECC based non-local computation protocols in more detail. A simple starting point may be to adapt the code based strategies of [56] to use entanglement-assisted codes.…”
Section: Why No N-to-m Theorem For N = M?mentioning
confidence: 99%
“…In fact, having a large amount of entanglement between these regions is also sufficient to reproduce any bulk interaction, though many questions remain as to how much entanglement is needed for a given interaction. See e.g [29]. for a discussion.…”
mentioning
confidence: 99%
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