2011
DOI: 10.1088/1751-8113/44/42/425203
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‘Complex source’ wavefields: sources in real space

Abstract: We consider a complexified Green function for the 3D Helmholtz operator. This function, G* = exp (ikR*)/R*, where , describes a Gaussian beam propagating along the z-axis. It satisfies a certain inhomogeneous Helmholtz equation in . The corresponding source distribution is a generalized function supported by a 2D surface, , which depends on the branch cut of the square root defining R*. We discuss various choices of the branch cut, and show that the corresponding surface can have a complicated structure. In o… Show more

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Cited by 19 publications
(8 citation statements)
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“…The total regularized potential is the sum of the results (18) and (20). Finally, the real potential is obtained by making the limit as p → 1:…”
Section: Potential Along Oz Axismentioning
confidence: 99%
See 2 more Smart Citations
“…The total regularized potential is the sum of the results (18) and (20). Finally, the real potential is obtained by making the limit as p → 1:…”
Section: Potential Along Oz Axismentioning
confidence: 99%
“…Mahillo-Isla et al [19], give a physical solution to the equivalent sources on the disk itself based on the evaluation of the field. Finally, Tagirdzhanov et al consider in [20] the complexified Green's function of the Helmholtz equation and the field sources that create that solution. In [21], they deal with the singularity that appears in the rim of the disk by covering it by a circular torus.…”
Section: Introductionmentioning
confidence: 99%
See 1 more Smart Citation
“…The most important example of a research of the first group is the theory of 'complex source' developed after pioneering papers [11,12] and [13] in both monochromatic and non-monochromatic cases. Singularities due to which these solutions do not satisfy the basic equation (1) in the whole space are described in detail in [14,15]. As an example of an exact solution satisfying (1) everywhere but involving a backward wave, we mention a nice simple solution found in [16].…”
Section: Introductionmentioning
confidence: 99%
“…Let us search for solutions of Eq. (1.1) in a classical form of Gaussian beams [7][8][9], which could be presented in Cartesian coordinate system X, Y, Z as below [10]:…”
Section: Introductionmentioning
confidence: 99%