2017
DOI: 10.1090/proc/13801
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Complete spectral sets and numerical range

Abstract: Abstract. We define the complete numerical radius norm for homomorphisms from any operator algebra into B(H), and show that this norm can be computed explicitly in terms of the completely bounded norm. This is used to show that if K is a complete Cspectral set for an operator T , then it is a complete M -numerical radius set, where M = 1 2 (C + C −1 ). In particular, in view of Crouzeix's theorem, there is a universal constant M (less than 5.6) so that if P is a matrix polynomial and T ∈ B(H), thenIn 2007, Mic… Show more

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Cited by 4 publications
(14 citation statements)
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References 12 publications
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“…We say that normalΩ is a Kwρ set for T if for every rational function f we have wρfalse(f(T)false)KfnormalΩ.The analogue notion of a complete Kwρ set is defined in a similar way. The case ρ=1 corresponds to the usual notion of K‐spectral sets while Kw2 sets are the K‐numerical radius sets from . We deduce the following result from Theorem .…”
Section: Applications To Spectral Setsmentioning
confidence: 70%
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“…We say that normalΩ is a Kwρ set for T if for every rational function f we have wρfalse(f(T)false)KfnormalΩ.The analogue notion of a complete Kwρ set is defined in a similar way. The case ρ=1 corresponds to the usual notion of K‐spectral sets while Kw2 sets are the K‐numerical radius sets from . We deduce the following result from Theorem .…”
Section: Applications To Spectral Setsmentioning
confidence: 70%
“…The following result, which is the main result of this paper, generalizes Theorem and the result from to the larger class of operator radii wρ. Theorem We assume K1 and ρ1 and set K=K2+1+(K2+1)24ρfalse(2ρfalse)K22ρK.Then, (a)Φ=K if and only if Φwρ=K for every unital homomorphism Φ:AB(H) from a Banach algebra scriptA satisfying the von Neumann inequality; (b)Φcb=K if and only if Φwρcb=K for every unital homomorphism Φ:AB(H) from an operator algebra scriptA. …”
Section: Operator Radii Of Homomorphisms Into B(h)mentioning
confidence: 83%
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