2009
DOI: 10.1016/j.disc.2008.10.002
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Complete solution for the rainbow numbers of matchings

Abstract: For a given graph H and n ≥ 1, let f (n, H) denote the maximum number c for which there is a way to color the edges of the complete graph K n with c colors such that every subgraph H of K n has at least two edges of the same color. Equivalently, any edge-coloring of K n with at least rb(n, H) = f (n, H) + 1 colors contains a rainbow copy of H, where a rainbow subgraph of an edge-colored graph is such that no two edges of it have the same color. The number rb(n, H) is called the rainbow number of H. Erdős, Simo… Show more

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Cited by 64 publications
(37 citation statements)
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“…is a bad P k−1 in F 0 , a contradiction to (5). but v is an isolated vertex in G * , then we have at least n−(t−1)−1 s−2 > ⌊n/s⌋ + 2(k − 1) − 2 edges meeting L but not belonging to F 0 , which is a contradiction.…”
Section: Proofmentioning
confidence: 83%
See 1 more Smart Citation
“…is a bad P k−1 in F 0 , a contradiction to (5). but v is an isolated vertex in G * , then we have at least n−(t−1)−1 s−2 > ⌊n/s⌋ + 2(k − 1) − 2 edges meeting L but not belonging to F 0 , which is a contradiction.…”
Section: Proofmentioning
confidence: 83%
“…They proved that ex(n, s, M k−1 ) + 2 ≤ ar(n, s, M k ) ≤ ex(n, s, M k−1 ) + k, where the lower bound holds for every n, and the upper bound holds for n ≥ sk + (s − 1)(k − 1). For s = 2, Schiermeyer [40] proved that ar(n, 2, M k ) = ex(n, 2, M k−1 ) + 2 for k ≥ 2 and n ≥ 3k + 3, and this condition was further released to all n ≥ 2k + 1 by Chen, Li and Tu [5] and by Fujita, Kaneko, Schiermeyer and Suzuki [17], independently.…”
Section: Introductionmentioning
confidence: 97%
“…Anti-Ramsey numbers were introduced by Erdős et al [8]. Various results about this extremal function have been obtained since then: [1,10,14,11,2,12,17,15,13,16,4] to name a few.…”
Section: Introductionmentioning
confidence: 97%
“…. , v q }) = ∅ since otherwise T n contains a K 3,3 -minor (with one part {v 4 , v 5 , v 6 } and the other part 4 , v j } contains two edge-disjoint 3K 2 , say M 1 and M 2 . Assume c(v j v 2 ) = c(e) for some M 1 .…”
Section: Introductionmentioning
confidence: 99%
“…Hence, v j u i ∈ E(T n ) for some i ∈ [3] and j ≥ 5. 4 , v 5 } contains two edgedisjoint 3K 2 , say M 1 and M 2 . Assume c(v 5 v 2 ) = c(e) for some M 1 .…”
Section: Introductionmentioning
confidence: 99%