“…Using the same poles and residues as before for this function to give cos(z) csc 3 3 (1.51) and (3) (z) = csc 4 (z)− 2 3 csc 2 (z), the offending term cancels and the three stages of integration yield − 1 6 (cot(z) + z). Discarding the analytical term, −z/6, we put f (z) = − 1 6 cot(z), and use the same poles and residues as before to give 4 (1.53) and…”