2009
DOI: 10.1016/j.jfa.2009.02.018
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Compactness of Hankel operators and analytic discs in the boundary of pseudoconvex domains

Abstract: Using several complex variables techniques, we investigate the interplay between the geometry of the boundary and compactness of Hankel operators. Let β be a function smooth up to the boundary on a smooth bounded pseudoconvex domain Ω ⊂ C n . We show that, if Ω is convex or the Levi form of the boundary of Ω is of rank at least n − 2, then compactness of the Hankel operator H β implies that β is holomorphic "along" analytic discs in the boundary. Furthermore, when Ω is convex in C 2 we show that the condition … Show more

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Cited by 21 publications
(18 citation statements)
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“…Our first result gives a necessary condition for compactness of Hankel operators; the case q = 1 and n = 2 is in [6] (for symbols in C(Ω)), the case q = 1 but general n is in [7] (for symbols in C ∞ (Ω)).…”
Section: Introduction and Resultsmentioning
confidence: 94%
See 1 more Smart Citation
“…Our first result gives a necessary condition for compactness of Hankel operators; the case q = 1 and n = 2 is in [6] (for symbols in C(Ω)), the case q = 1 but general n is in [7] (for symbols in C ∞ (Ω)).…”
Section: Introduction and Resultsmentioning
confidence: 94%
“…We also note that (n − 1)-dimensional polydiscs in bΩ are open subsets of a complex hyperplane. Indeed, the argument in [11], section 2 (see also [7], Lemma 2) shows that if the supporting real hyperplane to Ω at a point is {x n = 0} in suitable coordinates, then the embedding ψ maps into the complex hyperplane {z n = 0}.…”
Section: Corollarymentioning
confidence: 99%
“…But the domain Ω is convex which implies that the disk F(D) is an affine disk (see [FS98,ČŞ09]). Using Lemma 2 we can thus assume that there exists…”
Section: Theorem Let ω Be a Bounded Pseudoconvex Domain Inmentioning
confidence: 99%
“…It is clear that H φ is a bounded operator; however, its compactness depends on both the function theoretic properties of the symbol φ as well as the geometry of the boundary of the domain (see [6]). …”
mentioning
confidence: 99%
“…This will be enough to conclude that N 1 is compact on L 2 (0,1) ( ) The proof of the fact that 0 is B-regular is essentially contained in [5, Lemma 10.1] together with the following fact: Let be a smooth bounded pseudoconvex domain in C 2 . If H z and H w are compact on A 2 ( ) then there is no analytic disc in b (see[6, Corollary 1]).…”
mentioning
confidence: 99%