2015
DOI: 10.1016/j.jctb.2015.06.001
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Coloring digraphs with forbidden cycles

Abstract: Let k and r be two integers with k ≥ 2 and k ≥ r ≥ 1. In this paper we show that (1) if a strongly connected digraph D contains no directed cycle of length 1 modulo k, then D is k-colorable; and (2) if a digraph D contains no directed cycle of length r modulo k, then D can be vertex-colored with k colors so that each color class induces an acyclic subdigraph in D. The first result gives an affirmative answer to a question posed by Tuza in 1992, and the second implies the following strong form of a conjecture o… Show more

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Cited by 19 publications
(23 citation statements)
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“…The restriction on the cycles lengths in Theorems 3 and 4 provide better bounds. In Theorem 3 whenever s < ⌊ k 2 ⌋, χ A (D) < k and in Theorem 4 whenever k = sp with s ≥ 3, χ A (D) ≤ s < k. Our results are different from those obtained by Chen et al (2015). However, these two cases lower their bound.…”
Section: Introductioncontrasting
confidence: 86%
See 1 more Smart Citation
“…The restriction on the cycles lengths in Theorems 3 and 4 provide better bounds. In Theorem 3 whenever s < ⌊ k 2 ⌋, χ A (D) < k and in Theorem 4 whenever k = sp with s ≥ 3, χ A (D) ≤ s < k. Our results are different from those obtained by Chen et al (2015). However, these two cases lower their bound.…”
Section: Introductioncontrasting
confidence: 86%
“…Concerning acyclic colorings, Neumann-Lara (1982) proved that for any fixed integers k and r with k ≥ r ≥ 2, whenever a digraph D contains no cycle of length 0 or 1 modulo r, then χ A (D) ≤ k. In this direction, Chen et al (2015) gave a more general result. They proved for integers k and r with k ≥ 2 and k ≥ r ≥ 1 that: i) if a digraph D contains no cycle of length 1 modulo k, then D can be colored with k colors so that each color class is a stable set; ii) if a digraph D contains no cycle of length r modulo k, then D can be colored with k colors so that each color class induces an acyclic subdigraph of D; iii) if an undirected graph G contains no cycle of length r modulo k, then G is k-colorable if r = 2 and (k + 1)-colorable otherwise.…”
Section: Introductionmentioning
confidence: 99%
“…More generally, one could investigate the minimum number cycles of length r mod k in a graph of chromatic number at least, say, f (r, k). With regards to the existence of such cycles, Chen, Ma and Zang [9] proved that any graph with chromatic number greater than k must contain a cycle of length r mod k for r ∈ {0, . .…”
mentioning
confidence: 99%
“…Diwan, Kenkre and Vishwanathan [13] conjectured that for every pair of integers m and k, if graph G has no cycle of length m modulo k, then the chromatic number of G is at most k + o(k). This was resolved by Chen, Ma and Zang in a recent paper [8], where they also studied the relations between cycle lengths modulo k and chromatic number of digraphs.…”
Section: Cycles Of Consecutive Lengths and Chromatic Numbermentioning
confidence: 99%