Abstract. M. Bestvina has shown that for any given torsion-free CAT(0) group G, all of its boundaries are shape equivalent. He then posed the question of whether they satisfy the stronger condition of being cell-like equivalent. In this article we prove that the answer is "Yes" in the situation where the group in question splits as a direct product with infinite factors. We accomplish this by proving an interesting theorem in shape theory.1. Introduction. The CAT(0) condition is a geometric notion of nonpositive curvature, similar to the definition of Gromov δ-hyperbolicity. A geodesic space X is called CAT(0) if it has the property that geodesic triangles in X are "no fatter" than geodesic triangles in euclidean space (see [6, Section II.1] for a precise definition). The visual or ideal boundary of X, denoted ∂X, is the collection of geodesic rays emanating from a chosen basepoint. It is well-known that ∂X is well-defined and independent of the choice of basepoint. Furthermore, when given the cone topology, X ∪ ∂X is a Z-set compactification for X. A group G is called CAT(0) if it acts geometrically (i.e. properly discontinuously and cocompactly by isometries) on some CAT(0) space X. In this setup, we call X a CAT(0) G-space and ∂X a CAT(0) boundary of G. We say that a CAT(0) group G is rigid if it has only one topologically distinct boundary.It is well-known that if G is negatively curved (acts geometrically on a Gromov δ-hyperbolic space) or if G is free abelian then G is rigid. Apart from this, little is known concerning rigidity of groups. P. L. Bowers and K. Ruane showed that if G splits as the product of a negatively curved group with a free abelian group, then G is rigid [5]. Ruane proved later in [25] that if G splits as a product of two negatively curved groups, then G is rigid. T. Hosaka has extended this work to show that in fact it suffices