“…For the rest of the proof, we may thus assume A is not split . If (A, σ) is hyperbolic, then it follows from [6] that the split component of (C(A, σ), σ) is isotropic, hence (b)⇒(c). Conversely, if (c) holds, then [11, (8.5)] shows that (C 0 (ϕ), τ 0 ) is hyperbolic, hence (C + (ϕ), τ + ) also is hyperbolic, proving (c)⇒(b).…”