“…Since Thus, we get that (x + 3) h(P i ), where 2 i 28 and i = 5, 11, 17, 23. Therefore, (x +3) h(C j ), (3 j 14, j = 9) by Lemma 2.4(1), (4) and Lemma 2.6(2), (x +3) h(T 1,1,k ), (2 k 12, k = 7) by Lemma 2.4 (2), (x +3) h(D l ), (4 l 7) by Lemma 2.4(6)-(8), (10) and Lemma 2.6(2), and (x +3) h(T 1,2,t ), (…”