1996
DOI: 10.1016/0022-328x(96)06171-2
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Chemistry of diamino-ligated methylpalladium(II) alkoxides and aryloxides (Part II): methoxide formation and carbonylation reactions

Abstract: Reaction of N-ligated methylpalladium(II) alkoxide and aryloxide complexes [Pd(Me)(OR)(N ~ N)] (R = Ph, CH(CF3)2; N ~ N = trneda (N, N,N', N'-tetramethylethylenediamine) or bpy (2,2'-bipyridyl)) with carbon monoxide produces the corresponding methylesters in high yields. The insertion takes place either into the Pd-Me bond (aryloxide complexes) or into the Pd-OR bond (alkoxide complexes). Methylpalladium(II) methoxide complexes [Pd(Me)(OMe)(N ~ N)] (N ~ N = tmeda, bpy) have been generated in situ by aryloxide-… Show more

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Cited by 28 publications
(24 citation statements)
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“…1 The isoelectronic relationship between alkoxide and alkyl ligands suggests that they may display similar chemistry. Indeed, low-valent group 10 metal-oxygen bonds have been shown to participate in a number of typical organometallic reactions, including C-O bond forming reductive elimination, 2 β-H elimination, 3 and insertion reactions with unsaturated molecules such as CO [4][5][6][7][8][9][10][11][12][13] and alkenes. 14 However, the presence of lone pairs on the oxygen atom and the "hard" character of O-based ligands point to differences in stability and reactivity that may occur for these species relative to carbon-based analogues.…”
Section: Introductionmentioning
confidence: 99%
See 1 more Smart Citation
“…1 The isoelectronic relationship between alkoxide and alkyl ligands suggests that they may display similar chemistry. Indeed, low-valent group 10 metal-oxygen bonds have been shown to participate in a number of typical organometallic reactions, including C-O bond forming reductive elimination, 2 β-H elimination, 3 and insertion reactions with unsaturated molecules such as CO [4][5][6][7][8][9][10][11][12][13] and alkenes. 14 However, the presence of lone pairs on the oxygen atom and the "hard" character of O-based ligands point to differences in stability and reactivity that may occur for these species relative to carbon-based analogues.…”
Section: Introductionmentioning
confidence: 99%
“…The best characterized CO migratory reactions with Ni−O bonds involve complexes featuring aryloxide ligands such as Ni(Me)(O- p -C 6 H 4 CN)L 2 (L = PEt 3 ; L 2 = 2,2‘-bipyridyl), for which spectroscopic evidence for the formation of an acyl intermediate was found, indicating a greater reactivity of the Ni−Me bond in this case 5c 5a, although the reasons for this remain unclear. A key role for the O-based lone pairs in facilitating the migratory insertion process has been identified, although the relative strengths of the M−O and M−C bonds may also be important …”
Section: Introductionmentioning
confidence: 99%
“…Complex Am may evolve through the stepwise substitution of its TFA – ligands with other donors in solution, such as carbon monoxide, alkene (in the dihapto bonding mode), or a methanol solvent molecule. As suggested in the literature, methanol likely precedes the CO coordination to give the adduct [(N-N)­Pd­(TFA)­(CH 3 OH)] + ·[TFA] − , 2m a , in Figure , where the two counterions are held together by a H-bonding interaction with O 3 –H and H···O 1 distances of 1.04 and 1.48 Å, respectively.…”
Section: Resultsmentioning
confidence: 71%
“…The Pd complex reacts with the alcohol, allowing the formation of the active species B . The successive insertion of CO leads to the alkoxycarbonyl–palladium complex C , where the subsequent alkene’s coordination and insertion afford the five-membered palladacycle D . , From the latter, the complex E is obtained via another CO insertion passing through a six-membered palladacycle with the esteric carbonyl coordinated to the Pd center…”
Section: Introductionmentioning
confidence: 99%
“…For the dinuclear palladium aryloxides, Pd 2 L 2 (OAr) 2 (L = dmpm, dppm; Ar = Ph, OC 6 H 3 -2,6-Me), CO insertion predominantly occurs at the Pd−Pd bond, although the possibility of CO insertion into the Pd−O bond is also suggested . Methylpalladium(II) phenoxides, L 2 Pd(Me)(OPh) (L 2 = (PMe 3 ) 2 , dppe, tmeda, bpy), react with CO to produce phenyl acetate, MeCO 2 Ph . In this reaction, however, L 2 Pd(COMe)(OPh) rather than L 2 Pd(Me)(CO 2 Ph) is assumed to be the intermediate.…”
Section: Introductionmentioning
confidence: 99%