1972
DOI: 10.1002/chin.197243265
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ChemInform Abstract: SYNTH. VON PYRIDAZIN‐HYDRAZINEN MIT HYPOTENSIVER WIRKUNG 2. MITT.

Abstract: Das Dichlor‐pyridazin (II) reagiert mit sekundären Aminen zu den Amino‐pyridazinen (III), mit Morpholin zum Bis‐morpholino‐pyridazin (I).

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“…6-Chloro-3-[4-(2-methoxy phenyl)-1piperazinyl]pyridazine (II-7). A mixture of 3,6-dichloropyridazine (14.9 g, 0.1 mol) and l-(2-methoxyphenyl)piperazine (36 g, 0.2 mol) in C2H6OH (200 mL) was refluxed for 10 h. After evaporation of the solvent, the residue was triturated with H20, and the insolube material was filtered and crystallized from EtOAc: yield 21.5 g; NMR (Me2SO-d6) 8 3.08 (t, 4 H, «/Ch2ch2 = 5.5 Hz, CH2NC6H3) 3.74 (t, 4 H, CH2N), 3.81 (s, 3 H, Cti30), 6.9-7.2 (m, 4 H, phenyl protons), 7.48 (d, 1 H, -JH4-h5 = 10 Hz, H5), 7.61 (d, 1 H, H4).…”
Section: Methodsmentioning
confidence: 99%
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“…6-Chloro-3-[4-(2-methoxy phenyl)-1piperazinyl]pyridazine (II-7). A mixture of 3,6-dichloropyridazine (14.9 g, 0.1 mol) and l-(2-methoxyphenyl)piperazine (36 g, 0.2 mol) in C2H6OH (200 mL) was refluxed for 10 h. After evaporation of the solvent, the residue was triturated with H20, and the insolube material was filtered and crystallized from EtOAc: yield 21.5 g; NMR (Me2SO-d6) 8 3.08 (t, 4 H, «/Ch2ch2 = 5.5 Hz, CH2NC6H3) 3.74 (t, 4 H, CH2N), 3.81 (s, 3 H, Cti30), 6.9-7.2 (m, 4 H, phenyl protons), 7.48 (d, 1 H, -JH4-h5 = 10 Hz, H5), 7.61 (d, 1 H, H4).…”
Section: Methodsmentioning
confidence: 99%
“…3.90 (t, 4 H, CH20), 6.27 (d, 2 H, JH^h3 = 2.5 Hz, pyrrol H3), 6.32 (d, 1 H, JH4-H5 = 10 Hz, H4), 6.85 (d, 2 H, pyrrol H2), 6.90 (d, 1 H, H5), 7.65 (s, 1 , NH). IV-(2,5-Dimethyl-Iff -pyrrol-1-yl)-IV-methyl-6-(4morpholinyl)-3-pyridazinamine (VI-39), (a) 80% NaH in mineral oil (6.3 g, 0.21 mol) was added to a solution of VI-30 (31 g, 0.1 mol) in anhydrous DMF (250 mL).…”
Section: Methodsmentioning
confidence: 99%
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