1977
DOI: 10.1002/chin.197729136
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ChemInform Abstract: REACTION OF UNSATURATED N‐CHLORAMINES. THE NITRENIUM ION QUESTION

Abstract: Die intramolekulare Cyclisierung von verschiedenen N‐Chloraminen wird bei unterschiedlichen Reaktionsbedingungen (Variation des Lösungsmittels, der Reaktionsdauer, des Katalysators) in neutralem Medium untersucht.

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Cited by 2 publications
(5 citation statements)
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“…Trans ( 14), CD3CN, 80 °C, 160 Hz; CD3CN, 20 °C, 156 Hz. Line widths at 80 °C in CD3CN (P-decoupled) were relatively narrow for an l70 resonance: trans (14), 40 Hz; cis (13), 72 Hz. Small differences in ,70 NMR parameters for axial and equatorial 170 have been noted previously for cyclic 3',5'-monophosphate, diesters like 5.…”
Section: Resultsmentioning
confidence: 98%
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“…Trans ( 14), CD3CN, 80 °C, 160 Hz; CD3CN, 20 °C, 156 Hz. Line widths at 80 °C in CD3CN (P-decoupled) were relatively narrow for an l70 resonance: trans (14), 40 Hz; cis (13), 72 Hz. Small differences in ,70 NMR parameters for axial and equatorial 170 have been noted previously for cyclic 3',5'-monophosphate, diesters like 5.…”
Section: Resultsmentioning
confidence: 98%
“…Me2C(CN)0* + P(OR)3 -Me2CCN + OP(OR)3 ( 10) is quite reasonable. 14 We showed earlier15 that alkoxy radicals transfer oxygen to phosphorus (step 9) with retention of configuration, sequence 11. A phosphoranyl radical, 15, doubtless is Step 1 lb with Z = Me2C(CN)' is particularly favored. AIBN/02 oxidations of phenyl phosphites occur readily, whereas with Z-BuOOBu-Z displacement of phenoxy radical by ZerZ-butoxy radical results.…”
Section: Discussionmentioning
confidence: 95%
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“…The same compound is formed (56%) besides five other products (18%) and starting amine (26%) when 1 is treated in boiling methanol for 36 h. The mechanisms of these reactions will be discussed elsewhere. 13 The comparison of the NMR spectrum of 2 with those of 6 and 7 (see below) allows us to assign without any doubt a "nontwisted" homobrendane structure 214 to the solvolysis product of JV-chloroamine 1.…”
Section: Resultsmentioning
confidence: 99%
“…Furthermore, on the basis of chemical arguments, the methoxy group was expected to be exo. 13 Consequently proton H8 should appear as a doublet (90°dihedral angle between C5H5 and CeHg) which must be the one at 2.56 ppm. The signal at 3.27 ppm can only be due to proton H5 deshielded by the methoxy group.…”
Section: Resultsmentioning
confidence: 99%