2005
DOI: 10.1016/j.aop.2005.05.007
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Casimir energy for a dielectric cylinder

Abstract: In this paper we calculate the Casimir energy for a dielectric-diamagnetic cylinder with the speed of light differing on the inside and outside. Although the result is in general divergent, special cases are meaningful. The well-known results for a uniform speed of light are reproduced. The self-stress on a purely dielectric cylinder is shown to vanish through second order in the deviation of the permittivity from its vacuum value, in agreement with the result calculated from the sum of van der Waals forces. T… Show more

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Cited by 61 publications
(74 citation statements)
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“…For example, keeping none of those corrections, that is setting M = 0, we get for p = 1, e(1) ≈ −0.0010847. Keeping three terms is sufficient to find that e(1) is less than 10 −6 ; indeed, the circular cylinder value is e(1) = 0 [21,22,23,24,25]. This function e(p) is plotted in Fig.…”
Section: Dielectric Boundary At R = Amentioning
confidence: 94%
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“…For example, keeping none of those corrections, that is setting M = 0, we get for p = 1, e(1) ≈ −0.0010847. Keeping three terms is sufficient to find that e(1) is less than 10 −6 ; indeed, the circular cylinder value is e(1) = 0 [21,22,23,24,25]. This function e(p) is plotted in Fig.…”
Section: Dielectric Boundary At R = Amentioning
confidence: 94%
“…[21] to obtain the weakcoupling Casimir self-energy for a purely dielectric wedge, where µ 1 = µ 2 = 1. We can only examine the coefficient of (ǫ 1 − ǫ 2 ) 2 because the result is divergent in higher orders.…”
Section: Dielectric Boundary At R = Amentioning
confidence: 99%
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“…Although the first two orders in λ identically vanish, a divergence in the energy (14) does occur in O(λ 3 ).…”
Section: Exponential Regulatormentioning
confidence: 98%