“…Let G = C 4 and N = 2C4 . Then[4, Corollary 8] shows that the pair (C 4 , 2C 4 ) is capable, and sod ∧ (C 4 , 2C 4 ) = 1 |2C 4 ||C 4 | x∈C4 | Let G = D 8and N be the subgroup a 2 , ab of G. A computation similar to Example 4.1 shows that the pair (D 8 , a 2 , ab ) is capable, andd ∧ (D 8 , a 2 , ab ) = 1 | a 2 , ab ||D 8 | x∈D8 | a 2 ,ab C ∧ (…”