2006
DOI: 10.1016/j.cam.2005.02.001
|View full text |Cite
|
Sign up to set email alerts
|

Can a minimal degree 6 cubature rule for the disk have all points inside?

Abstract: We use positivity and extension properties of moment matrices to prove that a 10-node (minimal) cubature rule of degree 6 for planar measure on the closed unit diskD cannot have all nodes inD . We construct examples showing that such rules may have as many as 9 points inD, and we provide similar examples for the triangle.

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
1

Citation Types

0
2
0

Year Published

2013
2013
2018
2018

Publication Types

Select...
3

Relationship

1
2

Authors

Journals

citations
Cited by 3 publications
(2 citation statements)
references
References 20 publications
0
2
0
Order By: Relevance
“…Minimal representing measures supported on prescribed sets arise when one wants to construct a minimal cubature formula. For a moment matrix approach see [12], [11]. For a different approach see [17].…”
Section: Introductionmentioning
confidence: 99%
“…Minimal representing measures supported on prescribed sets arise when one wants to construct a minimal cubature formula. For a moment matrix approach see [12], [11]. For a different approach see [17].…”
Section: Introductionmentioning
confidence: 99%
“…• The bad reason is that our proofs will in general not be able to guarantee the nodes to be contained in the support. • There are examples where the minimal number of nodes can only be reached if one does not insist on all nodes being contained in the support, e.g., when one searches a quadrature rule of degree 6 for the Lebesgue measure on the closed unit disk [EFP,Theorem 1.1]. • For many important measures (e.g., the Gaussian measure on R n ) the requirement to lie in the support is anyway empty and it seems more important that the nodes are not too "far out", at least those with significant weight.…”
mentioning
confidence: 99%