1987
DOI: 10.1088/0022-3700/20/19/007
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Calculation of the P- and T-odd spin-rotational Hamiltonian of the PbF molecule

Abstract: Abstract. The electron wavefunctions for two states of the PbF molecule are calculated. For the ground state of the molecule, tensor components of the hyperfine interaction of the valence electron with the nuclear spin of Pb, electric and magnetic dipole moments and electron matrix elements of P-odd and P, T-odd interactions are calculated. In accordance with the calculation an effective spin-rotational Hamiltonian for the molecule is given. The Hamiltonian includes the parity-non-conserving terms and the inte… Show more

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Cited by 88 publications
(106 citation statements)
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“…This is the T,P-odd interaction which mixes states of opposite parity in atoms and molecules [16,17]. Relativistic Hamiltonian of the interaction is given by the following expression [16,20,21]:…”
Section: Theorymentioning
confidence: 99%
“…This is the T,P-odd interaction which mixes states of opposite parity in atoms and molecules [16,17]. Relativistic Hamiltonian of the interaction is given by the following expression [16,20,21]:…”
Section: Theorymentioning
confidence: 99%
“…Recently, the E eff value for the 3 ∆ 1 state was estimated in the scalar-relativistic approximation by Meyer et al [16] and the method used for calculation of E eff is close in essence to that developed by us earlier [17] and applied to first two-step calculations of the PbF molecule [14,17]. In the present work, a more reliable value of E eff is calculated using the advanced two-step techniques developed by us later [18,19,20,21] is not the ground state, its radiative lifetime is also required.…”
mentioning
confidence: 91%
“…It is presented by the expression E eff = W d |Ω|, where W d is a parameter of the P,T-odd molecular Hamiltonian that is given in Refs. [4,14,15] …”
mentioning
confidence: 99%
“…A very useful semiempirical expression for K ∼ α 2 Z 3 is proposed in [20] that is well working for s, p electrons though it is questionable for f electrons. E eff is given by [21][22][23]):…”
Section: Methodsmentioning
confidence: 99%