1959
DOI: 10.2307/2527605
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Calculation of Chi-Square to Test the No Three-Factor Interaction Hypothesis

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Cited by 37 publications
(24 citation statements)
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“…Roy had carefully distinguished between probability models for multidimensional contingency tables based on which dimensions are considered fixed factors versus random responses; in a regression setting, these are, respectively, independent and dependent variables. Roy and Kastenbaum had worked extensively on hypotheses and tests of no interaction for three-way tables (Roy andKastenbaum 1955, 1956;Roy 1957;Kastenbaum and Lamphiear 1959).…”
Section: Foundationsmentioning
confidence: 99%
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“…Roy had carefully distinguished between probability models for multidimensional contingency tables based on which dimensions are considered fixed factors versus random responses; in a regression setting, these are, respectively, independent and dependent variables. Roy and Kastenbaum had worked extensively on hypotheses and tests of no interaction for three-way tables (Roy andKastenbaum 1955, 1956;Roy 1957;Kastenbaum and Lamphiear 1959).…”
Section: Foundationsmentioning
confidence: 99%
“…The technology was applied to varied examples collectively encompassed by no prior analytic framework: testing second-order loglinear interaction in Bartlett's (1935) 2 3 data, and marginal homogeneity in Cochran's (1955) 2 3 drug comparison datasets and a 4 × 4 opthalmological comparison of paired left and right eyes; a two-factor ANOVA analog for an ordinal surgical sequel scored 0, 1, or 2; and a two-factor loglinear model for three-category litter depletion response data of Kastenbaum and Lamphiear (1959).…”
Section: Computational Unificationmentioning
confidence: 99%
“…More generally, for the 2 XJ XK tables we note that S2 given by (2.2.9), which is equal to gkM(k)gk given in (2.2.4), can be used to test the hypothesis that the J measures fjk (j= 1, 2, ... , J) do not differ significantly from each other (see Appendix A2). To apply Plackett's analysis [23 ], the user would invert K+ 1 (J -1) X (J -1) matrices, and to apply the BFNRKLD test he would solve the set of (J -1) (K-1) simultaneous third-degree equations given in Roy and Kastenbaum [24] and Kastenbaum and Lamphiear [19] or he would solve the JK+2(J+K) nonlinear equations given in Darroch [8]. If this hypothesis is rejected, the subtraction of g'Qg from R2 k=l [as in (2.2.8) ] will then test the hypothesis that the difference between the J measures flk (j= 1, 2, * * *, J) can be explained simply in terms of the differences between the J means fj*-=Ek Z jk/K (j= 1, 2, * , J); i.e., the hypothesis Ho that with respect to the J X K measures (Pjk the interaction in the J X K twoway layout is zero.…”
Section: The 2 X J X K Contingency Tablementioning
confidence: 99%
“…For the more general I X J X K three-way table, Roy and Kastenbaum [24 ] have extended the definition of zero three-factor interaction, and they have constructed a test of the hypothesis that this interaction is zero, a test which is identical to the tests given by Bartlett [2] and Norton [22] for the special case of the 2 X 2 X K table. To solve this system of equations, Kastenbaum and Lamphiear [19 ] have generalized Norton's iterative procedure and have adapted it for a high-speed computer. (When min [I, J, K] = 2, these equations are of the third-degree.)…”
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confidence: 99%
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