“…Since points of a sublocale are precisely the points of the locale belonging to the sublocale, there is a point p ∈ Pt(L) such that p ∈ G. Consequently, p ∈ o(a n ) for each n, so that c(p) = {p, 1} ⊆ o(a n ) and hence p ∨ a n = 1. Since compact regular locales are normal, for each n there exists c n ∈ Coz L such that c n ≤ p and c n ∨ a n = 1 (see [1,Corollary 8.3.2]). Put c = c n , so that c ∈ Coz L, c ≤ p < 1, and T. Dube c ∨ a n = 1 for every n. Consequently, c(c) ⊆ o(a n ) for every n, and so…”