1990
DOI: 10.2307/2048364
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C 1 is Uniformly Kadec-Klee

Abstract: A dual Banach space X is Kadec-Klee in the weak * topology if weak * and norm convergence of sequences coincide in the unit sphere of X. We shall consider a stronger, uniform version of this property. A dual Banach space X is uniformly Kadec-Klee in the weak * topology (UKK*) if for each e > 0 we can find a ó in (0, 1) such that every weak '-compact, convex subset C of the unit ball of X whose measure of norm compactness exceeds e must meet the (1-<5)-ball of X. We show in this paper that Cx(ß7), the space of … Show more

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Cited by 29 publications
(33 citation statements)
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“…Lennard proved in [20] that the trace class operators N (ℓ 2 , ℓ 2 ) has the weak* fixed point property. This result was extended by Besbes [3] to N (ℓ p , ℓ q ) with p −1 + q −1 = 1.…”
Section: Orlicz and Lorentz Sequence Spacesmentioning
confidence: 99%
See 1 more Smart Citation
“…Lennard proved in [20] that the trace class operators N (ℓ 2 , ℓ 2 ) has the weak* fixed point property. This result was extended by Besbes [3] to N (ℓ p , ℓ q ) with p −1 + q −1 = 1.…”
Section: Orlicz and Lorentz Sequence Spacesmentioning
confidence: 99%
“…Lennard proved in [20] that the space of trace class operators on a Hilbert space is weak* AUC. Equivalently, K(ℓ 2 ) is AUS.…”
Section: Introduction and Notationmentioning
confidence: 99%
“…Then the space ⊕T (H f ) can be isometrically embedded into T (H). By a result of Lennard [18] T (H) has property U KK . It follows that T (H), and so every subspace of it, has the fpp.…”
Section: The Rnp and The Fpp On The Predual Of Von Neumann Algebrasmentioning
confidence: 95%
“…In particular, by the uniqueness of the predual of a von Neumann algebra [35, p.135], A * is isomorphic to the 1 -sum ⊕J(H f ), f ∈ ext (S), where J(H f ) denotes the space of trace-class operators on H f , which can be embedded as a subspace of J(H), where H is the Hilbert space direct sum of H f , f ∈ ext (S). By a result of Lennard [27], J(H) has UKK. In particular, every subspace of J(H) has UKK.…”
Section: Proof By Assumption a Itself Is Not A µ-Atom So There Is mentioning
confidence: 98%