2007
DOI: 10.1016/j.jfa.2007.09.002
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Boundedly complete weak-Cauchy basic sequences in Banach spaces with the PCP

Abstract: It is proved that every non-trivial weak-Cauchy sequence in a Banach space with the PCP (the Point of Continuity Property) has a boundedly complete basic subsequence. The following result, due independently to S. Bellenot and C. Finet, is then deduced as a corollary. If a Banach space X has separable dual and the PCP, then every non-trivial weak-Cauchy sequence in X has a subsequence spanning an order-one quasi-reflexive space.

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Cited by 4 publications
(9 citation statements)
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“…As an easy consequence we also deduce from the above characterization of w * -PCP that every seminormalized basic sequence in a Banach space with PCP has a boundedly complete basic subsequence. This last result was obtained in [8].…”
Section: Introductionmentioning
confidence: 68%
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“…As an easy consequence we also deduce from the above characterization of w * -PCP that every seminormalized basic sequence in a Banach space with PCP has a boundedly complete basic subsequence. This last result was obtained in [8].…”
Section: Introductionmentioning
confidence: 68%
“…The following consequence, obtained in a different way in [8], shows how many separable and dual subspaces contains every Banach space with PCP.…”
Section: Now We Define a New Tree {Xmentioning
confidence: 98%
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“…As PCP is separably determined [1], that is, a Banach space satisfies PCP if every separable subspace has PCP, it is natural looking for a sequential characterization of PCP. In this sense, it has been proved in [12] that every semi-normalized basic sequence in a Banach space with PCP has a boundedly complete subsequence. The converse of the above result is false in general, but it is open for Banach spaces not containing 1 (see Remark 2 in [12]).…”
Section: Introductionmentioning
confidence: 99%
“…In this sense, it has been proved in [12] that every semi-normalized basic sequence in a Banach space with PCP has a boundedly complete subsequence. The converse of the above result is false in general, but it is open for Banach spaces not containing 1 (see Remark 2 in [12]). The goal of this note is to prove in Corollary 2.4 that there exists a family of Banach spaces failing PCP and not containing 1 such that every semi-normalized basic sequence has a boundedly complete subsequence.…”
Section: Introductionmentioning
confidence: 99%