1999
DOI: 10.1007/s002200050760
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Boundary Layers for the Navier-Stokes Equations¶of Compressible Fluids

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Cited by 57 publications
(79 citation statements)
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“…(1.5) In addition, Frid and Shelukhin [5] also proved the vanishing shear viscosity of global strong solutions for isentropic flows in the case of cylindric symmetry, and similar results can be found in [2,3,15] and references therein. This result was generalized to the non-isentropic flow in [8] with the heat conductivity coefficient satisfying C −1 (1 + θ q ) κ ≡ κ(ρ, θ) C(1 + θ q ), |κ ρ (ρ, θ )| C(1 + θ q ) (q > 1).…”
Section: Introductionsupporting
confidence: 55%
See 1 more Smart Citation
“…(1.5) In addition, Frid and Shelukhin [5] also proved the vanishing shear viscosity of global strong solutions for isentropic flows in the case of cylindric symmetry, and similar results can be found in [2,3,15] and references therein. This result was generalized to the non-isentropic flow in [8] with the heat conductivity coefficient satisfying C −1 (1 + θ q ) κ ≡ κ(ρ, θ) C(1 + θ q ), |κ ρ (ρ, θ )| C(1 + θ q ) (q > 1).…”
Section: Introductionsupporting
confidence: 55%
“…Frid and Shelukhin [5] first investigated the boundary layer effect of the compressible isentropic flow with cylindrical symmetry for the constant initial value, and proved the existence of the thickness of boundary layers (cf. Definition 1.2 below) as O(μ α )(0 < α < 1 2 ).…”
Section: Introductionmentioning
confidence: 99%
“…The similar definition of δ(ε) was proposed by the authors in [7], with W 1,1 g (Ω) substituted by L ∞ (Ω), to justify the Stokes-Blasius law δ(µ) ∼ √ µ of the laminar boundary-layer thickness for axially symmetric flows of a compressible fluid between two cylinders when the shear viscosity µ is small and the dilatational viscosity is kept constant. In the present paper, the choice of W 1,1 g (Ω) is due to the fact that Ω is unbounded.…”
Section: Remark 12mentioning
confidence: 99%
“…We introduce the following coordinate transformation: 12) then the boundaries r = a and r = b become (1.14)…”
Section: U(a T) = U(b T) = 0 T ∈ [0 T] (111)mentioning
confidence: 99%