“…Therefore,replacement of Pb with less toxic or non-toxic elements becomes an effective solution and has been investigated. [8][9][10] Isovalent substitution became aw ay to obtain lead-free halide perovskites NCs CsBX 3 (B = Sn 2+ ,G e 2+ ). [11,12] Unfortunately,t he Sn 2+ and Ge 2+ ions are extremely instable and oxidized easily to Sn 4+ and Ge 4+ ,r espectively.H eterovalent substitution can form lead-free perovskites NCs:f irstly,s ubstituting three Pb 2+ cations with two trivalent B 3+ cations A 3 B 2 X 9 (A = Cs,R b; B = Sb,B i) ; [13][14][15][16] secondly,s ubstituting two Pb 2+ cations with aq uadrivalent B 4+ cation Cs 2 BX 6 (B = Sn, Pd); [17,18] thirdly, substituting two Pb 2+ cations with am onovalent B + and at rivalent B' 3+ cations Cs 2 BB'X 6 (B = Ag, Na;B ' = Bi, Sb, In).…”