2000
DOI: 10.1016/s0012-365x(99)00196-x
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Bipartite covering graphs

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Cited by 11 publications
(16 citation statements)
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“…Theorem 2.1: Let W be a walk in a voltage graph X with initial vertex v. Then for each vertex (v, g) in X α for g ∈ G, there is a unique walk W g in X α that starts at (v, g) and projects down to W . Assume W = e Voltage graphs have been successfully used to obtain many instances of graphs with extremal properties; see [9], [4], [5], [3].…”
Section: Preliminariesmentioning
confidence: 99%
“…Theorem 2.1: Let W be a walk in a voltage graph X with initial vertex v. Then for each vertex (v, g) in X α for g ∈ G, there is a unique walk W g in X α that starts at (v, g) and projects down to W . Assume W = e Voltage graphs have been successfully used to obtain many instances of graphs with extremal properties; see [9], [4], [5], [3].…”
Section: Preliminariesmentioning
confidence: 99%
“…Assume G is connected. In [24] it is explained that the ordinary derived graph G α ′ is connected if and only if G ′ = G. In [4], a similar result is explained for a permutation derived graph, which involves the structure of the orbits when the local group acts on the set {1, 2, . .…”
Section: Connectivitymentioning
confidence: 89%
“…For any assignment α of edges in G to voltages in a group G, it is possible to find for any spanning tree T of G, a voltage assignment α ′ of edges in G to G, where the edges of T are assigned the identity permutation under α ′ and the resulting graphs G α and G α ′ are isomorphic [4], [24]. We will therefore focus on how to assign voltages to the edges that lie outside of a chosen spanning tree, also called the co-tree.…”
Section: Connectivitymentioning
confidence: 99%
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“…[2]) Let G be a non-bipartite graph with a generating voltage assignment ν in A which derives the covering graphG. ThenG is bipartite if and only if there exists a subgroup A e of index two in A such that for every cycle C, ν(C) ∈ A e if and only if the length of C is even.It is obvious that χ G (H) = 1 if and only if G is a null graph.…”
mentioning
confidence: 99%