2012
DOI: 10.1103/physreva.86.063609
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Beyond mean-field low-lying excitations of dipolar Bose gases

Abstract: We theoretically investigate various beyond mean-field effects on Bose gases at zero temperature featuring the anisotropic and long-range dipole-dipole interaction in addition to the isotropic and short-range contact interaction. Within the realm of the Bogoliubov-de Gennes theory, we consider static properties and low-lying excitations of both homogeneous and harmonically trapped dipolar bosonic gases. For the homogeneous system, the condensate depletion, the ground-state energy, the equation of state, and th… Show more

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Cited by 172 publications
(174 citation statements)
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“…Note that, in order to avoid any instability, we restricted ǫ dd in Fig. 1 to the maximum value one, so that the radicand in the Bogoliubov spectrum (23) remains positive when k → 0 [42,43]. We conclude that Eqs.…”
Section: Zero-temperature Resultsmentioning
confidence: 99%
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“…Note that, in order to avoid any instability, we restricted ǫ dd in Fig. 1 to the maximum value one, so that the radicand in the Bogoliubov spectrum (23) remains positive when k → 0 [42,43]. We conclude that Eqs.…”
Section: Zero-temperature Resultsmentioning
confidence: 99%
“…Thus, following Refs. [43,53], we can evaluate (25) by introducing an ultraviolet cutoff, where the interaction has to be renormalized by inserting the term m(nV k ) 2 2 k 2 , so that the divergent part is removed…”
Section: Zero-temperature Resultsmentioning
confidence: 99%
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“…In principle, pure liquid droplets in the absence of trapping should reach an equilibrium with an absence of growth [4,21]. On the other hand, time-of-flight expansion under a dipolar interaction is nontrivial but well studied [32,33], and it is modified by beyond mean-field effects [27]; these effects are isotropic and counteract magnetostriction. Mean-field hydrodynamic equations could not describe the expansion of our droplets.…”
mentioning
confidence: 99%
“…[25][26][27] the beyond mean-field correction to the chemical potential μ ¼ ð∂e=∂nÞ for a dipolar gas is given by μ bmf ≃ ð32gn=3 ffiffiffi π p Þ ffiffiffiffiffiffiffi ffi na 3 p ð1 þ 3 2 ϵ 2 dd Þ, where we have taken the lowest order expansion of the Q 5 function of Ref. [27] since ϵ dd is close to 1. Doing this we effectively neglect the imaginary part, which is very small compared to the real part, such that a long lifetime is still ensured, though it is only in a metastable equilibrium.…”
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confidence: 99%