Behavior of scaled-up sodium alanate hydrogen storage tanks during sorption

Neutrons for industry

“…For applications where a relatively slow charging of the tank (2 h) is permissible, as for stationary large scale storages, hydrogen solid-state storage is an interesting alternative due to its low pressure operation and binding of the hydrogen in a safe chemical form [35][36][37].…”

The kinetics of lightweight solid-state hydrogen storage materials: A review

“…In a simulation that used sodium alanate as the hydrogen storage materials, Raju et al [32,33] concluded that heat exchanger with a helical tube design is able to remove the heat more effective than to that of straight-parallel tube design. Bellosta von Colbe et al [39] investigated a tubular reactor with a porous sintered metal tube reactor design using NaAlH 4 doped with 2 mol% (TiCl 3 e0.3AlCl 3 ) and 5 mol% carbon with 8 kg of storage material. The kinetics and cycling results for 1 to 10 activation cycles after 10 min showed that an 80% capacity was achieved [39].…”

“…Bellosta von Colbe et al [39] investigated a tubular reactor with a porous sintered metal tube reactor design using NaAlH 4 doped with 2 mol% (TiCl 3 e0.3AlCl 3 ) and 5 mol% carbon with 8 kg of storage material. The kinetics and cycling results for 1 to 10 activation cycles after 10 min showed that an 80% capacity was achieved [39]. The thermal conductivity of metal hydride can be further improved with heat conductive additives, such as aluminum powder and carbon nanotubes [25].…”

Cyclic stability and structure of nanoconfined Ti-doped NaAlH 4

“…To date, NaAlH 4 is one of the most promising hydrogen storage compounds from a commercial stand point due to its low cost, moderate operating temperature and practical operating pressures. As such, ongoing research is focused on optimizing large scale NaAlH 4 tanks for energy storage applications [2,3]. It is well known that NaAlH 4 decomposes, releasing hydrogen in 3 steps: 3NaAlH 4 $Na 3 AlH 6 þ 2Al þ 3H 2 ; 3:70 wt:%H (1) Na 3 AlH 6 $3NaH þ Al þ 3 = 2 H 2 ; 1:85 wt:%H (2) NaH$Na þ 1 = 2 H 2 ; 1:85 wt:%H…”