2021
DOI: 10.48550/arxiv.2104.09965
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Avoiding squares over words with lists of size three amongst four symbols

Abstract: In 2007, Grytczuk conjecture that for any sequence (ℓ i ) i≥1 of alphabets of size 3 there exists a square-free infinite word w such that for all i, the i-th letter of w belongs to ℓ i . The result of Thue of 1906 implies that there is an infinite square-free word if all the ℓ i are identical. On the other, hand Grytczuk, Przyby lo and Zhu showed in 2011 that it also holds if the ℓ i are of size 4 instead of 3.In this article, we first show that if the lists are of size 4, the number of square-free words is at… Show more

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Cited by 3 publications
(4 citation statements)
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“…The idea to find the sequence of coefficients is identical to the one used in Section 5 of [5]. We use a computer to first compute the set Λ of minimal forbidden factors and we can then find a set of coefficients with the desired properties.…”
Section: Verifying Lemma 3 and Lemmamentioning
confidence: 99%
See 1 more Smart Citation
“…The idea to find the sequence of coefficients is identical to the one used in Section 5 of [5]. We use a computer to first compute the set Λ of minimal forbidden factors and we can then find a set of coefficients with the desired properties.…”
Section: Verifying Lemma 3 and Lemmamentioning
confidence: 99%
“…Our proof relies on the same idea as the technique used in [5] (in fact, we recommend reading Lemma 2 of [5] before any proof from the current article since it is a less technical proof using the same central idea). More precisely, it relies on a recent counting argument [6,10] and on some ideas introduced by Koplakov and improved by Shur [2,7].…”
Section: Introductionmentioning
confidence: 99%
“…The argument used for our lower bound is a simple counting technique recently introduced in [13] and already used in a few different settings [5,11,14,17]. In the setting of combinatorics on words a similar technique was already known under the name power series method [2,3,9,12].…”
Section: Introductionmentioning
confidence: 99%
“…Currently the best general result confirms it for alphabets of size 4 (see [13,12,26] for three different proofs). Recently Rosenfeld [27] proved that it holds when the union of all alphabets is a 4-element set.…”
Section: Introductionmentioning
confidence: 99%