2007
DOI: 10.1002/anie.200700530
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[AuGe18{Si(SiMe3)3}6]: A Soluble Au–Ge Cluster on the Way to a Molecular Cable?

Abstract: Metalloid clusters of Group 14 have been established as a discrete group of cluster compounds [1,2] during the last years. [3,4] The metalloid clusters of the general formula [M n R m ] (n > m; M = Si, Ge, Sn, Pb) contain ligand-bound metal atoms as well as "naked" metal atoms. Since the "naked" metal atoms inside these clusters exhibit an oxidation state of 0, the average oxidation state of the metal atoms within metalloid Group 14 cluster compounds is between 0 and 1. Therefore, these cluster compounds can b… Show more

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Cited by 108 publications
(67 citation statements)
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“…The formation of 1 can be viewed in light of the previously suggested formation of the gold analogue of 3, that is, [(Ge 9 R 3 )Au I (Ge 9 R 3 )] − (4). 46 While 3 is made by reacting Ge 9 R 3 − with the salt-like Cu(I) compound with weakly coordinating anions, Cu(Al(OR) 4 ), 47 4 is made by a reaction with a salt with ligated Au(I), (PPh 3 )AuCl, just like the reaction with (PPh 3 ) 3 CuBr for the formation of 1. It has been speculated that the formation of 4 begins with a salt-metathesis reaction to form the neutral [(Ge 9 R 3 )Au−PPh 3 ], which then exchanges the neutral PPh 3 ligand with another anionic Ge 9 R 3 − to form [(Ge 9 R 3 )Au I (Ge 9 R 3 )] − , that is: 46…”
Section: ■ Results and Discussionmentioning
confidence: 99%
“…The formation of 1 can be viewed in light of the previously suggested formation of the gold analogue of 3, that is, [(Ge 9 R 3 )Au I (Ge 9 R 3 )] − (4). 46 While 3 is made by reacting Ge 9 R 3 − with the salt-like Cu(I) compound with weakly coordinating anions, Cu(Al(OR) 4 ), 47 4 is made by a reaction with a salt with ligated Au(I), (PPh 3 )AuCl, just like the reaction with (PPh 3 ) 3 CuBr for the formation of 1. It has been speculated that the formation of 4 begins with a salt-metathesis reaction to form the neutral [(Ge 9 R 3 )Au−PPh 3 ], which then exchanges the neutral PPh 3 ligand with another anionic Ge 9 R 3 − to form [(Ge 9 R 3 )Au I (Ge 9 R 3 )] − , that is: 46…”
Section: ■ Results and Discussionmentioning
confidence: 99%
“…The resulting bis- and tris-silylated cluster species [Ge 9 R 2 ] 2− (R = Si(TMS) 3 ) [14] and [Ge 9 R 3 ] − (R: various silyl groups) [15,16,17,18,19,20] are, due to their lower charge, soluble in common solvents (acetonitrile, thf, toluene). Subsequent reactions of the tris-silylated cluster [Ge 9 R 3 ] − (R: Si(TMS) 3 ) with coinage metal complexes, in most cases coinage metal phosphine complexes, commonly yield coinage metal-bridged cluster dimers, under the loss of the original ligand sphere of the transition metal [19,21,22]. However, there are also a few reports in which the Cu-phosphine bond is retained [18,23].…”
Section: Introductionmentioning
confidence: 99%
“…[6] Aside from structural similarities to known solid-state structures,c ompletely novel structures have also been observed within metalloid clusters,f or example,the empty polyhedral arrangement of 14 germanium atoms in {Li(thf) 2 } 3 {Ge 14 [E(SiMe 3 ) 3 ] 5 }( E= Si, Ge), [7,8] or the arrangement of 17 tin atoms in Sn 17 [GaCl(ddp)] 4 (ddp = HC(CMeNDipp) 2 ). [9] This structural variety shows that there is high complexity in the nanoscale regime,a nd the study of metalloid cluster compounds provides first insights into the seemingly simple process of the formation of ametal or semi-metal.…”
mentioning
confidence: 97%