1965
DOI: 10.1002/j.1538-7305.1965.tb01661.x
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Atomic Hydrogen as a Reducing Agent

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Cited by 31 publications
(9 citation statements)
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“…However, it is well known that H is more active than H 2 , as it can reduce metal oxides such as CuO at room temperature. 49 The poor activity of H 2 as a reducing agent compared with that of H is further confirmed here, following Li et al, 26 /Ti = −1.63 V). However the results obtained here were not so; metallic Sn, Co, and Ni were not produced in their solutions.…”
Section: Morphologies and Compositions Of The Ti-aunps Modifiedsupporting
confidence: 84%
“…However, it is well known that H is more active than H 2 , as it can reduce metal oxides such as CuO at room temperature. 49 The poor activity of H 2 as a reducing agent compared with that of H is further confirmed here, following Li et al, 26 /Ti = −1.63 V). However the results obtained here were not so; metallic Sn, Co, and Ni were not produced in their solutions.…”
Section: Morphologies and Compositions Of The Ti-aunps Modifiedsupporting
confidence: 84%
“…An obvious explanation for this is the formation of water from silicates under bombardment of excited hydrogen atoms. Evidence for this has been reported before in this laboratory (I), and by other workers (11,12).…”
Section: Nature Of the Surfacesupporting
confidence: 80%
“…A controlled experiment with the passage of H 2 gas overnight reveals that H 2 cannot reduce an aqueous solution of Na 2 PdCl 4 . In contrast, H is more active than H 2 and it can reduce metal oxides such as CuO at room temperature21. As mentioned above, Pd particles can form on the Al foil in the early stage of pitting corrosion, when the oxide film is not broken.…”
Section: Resultsmentioning
confidence: 99%
“…The H is produced as an intermediate of the pitting corrosion of Al below the oxide film20. It cannot reduce aluminum oxide21 because of the very low standard reduction potential of E° Al(OH) 3 /Al = −2.31 V, but it can diffuse through to the top of the oxide film22. The hydrogen electro-oxidation reaction continues on the top of the oxide film and the released electrons flow onto the surface of the formed Pd particles for further reduction of [PdCl x (OH) y ] 2− , leading to the growth of the Pd particles.…”
Section: Resultsmentioning
confidence: 99%