2020
DOI: 10.1021/acs.jced.9b01135
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Assessment of Thermochemical Data of γ-Butyrolactone from Experimental and Computational Studies

Abstract: Relevant thermochemical data of γ-butyrolactone (GBL), a compound of considerable industrial and environmental significance, obtained from experimental and computational studies are reported in this work. The standard (p° = 0.1 MPa) molar enthalpy of formation, at T = 298.15 K, in the gaseous phase, was determined from the enthalpy of combustion and vaporization, obtained by static bomb calorimetry in oxygen and by Calvet microcalorimetry, respectively. The enthalpy of formation in the gaseous phase was also d… Show more

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Cited by 4 publications
(6 citation statements)
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“…The isodesmic reaction: GHL + HCHO = GBL + CH 3 CH 2 CH 2 CHO has a reaction enthalpy of 7.41±0.97$-7.41 \pm 0.97$ kJ mol −1 ; in conjunction with the well‐known formation enthalpies of formaldehyde (109.229±0.096$-109.229 \pm 0.096$), n‐butanal 32 (205.7±0.92$-205.7 \pm 0.92$), and γ‐butyrolactone or GBL 30 (370.0±1.5$-370.0 \pm 1.5$), this yields a heat of formation of −439.5 ± 1.7 kJ mol −1 .…”
Section: Computational Resultsmentioning
confidence: 94%
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“…The isodesmic reaction: GHL + HCHO = GBL + CH 3 CH 2 CH 2 CHO has a reaction enthalpy of 7.41±0.97$-7.41 \pm 0.97$ kJ mol −1 ; in conjunction with the well‐known formation enthalpies of formaldehyde (109.229±0.096$-109.229 \pm 0.096$), n‐butanal 32 (205.7±0.92$-205.7 \pm 0.92$), and γ‐butyrolactone or GBL 30 (370.0±1.5$-370.0 \pm 1.5$), this yields a heat of formation of −439.5 ± 1.7 kJ mol −1 .…”
Section: Computational Resultsmentioning
confidence: 94%
“…For GVL, the two isodesmic reactions used, in combination with the reference molecule GBL for which the thermochemistry is known, 30 were GVL+HCHO=GBL+HC(O)CH3$$\begin{eqnarray} {\rm GVL + HCHO} & = & {\rm GBL} + {\rm HC(O)CH_3}\end{eqnarray}$$ GVL+HC(O)CH3=GBL+CH3normalC(O)CH3$$\begin{eqnarray} {\rm GVL} + {\rm HC(O)CH_3} & = & {\rm GBL} + {\rm CH_3C(O)CH_3} \end{eqnarray}$$with reaction enthalpies of 11.89±0.68$-11.89 \pm 0.68$ and 7.87±1.78$-7.87 \pm 1.78$ kJ mol −1 , respectively, computed from four composite methods, 31 namely CBS‐QB3, CBS‐APNO, G3, and G4. Formation enthalpies of formaldehyde (109.229±0.096$-109.229 \pm 0.096$), acetaldehyde (165.55±0.23$-165.55 \pm 0.23$), and propanone (216.93±0.27$-216.93 \pm 0.27$) 32 give an average value of −413.97 ± 2.01 kJ mol −1 (298.15 K).…”
Section: Computational Resultsmentioning
confidence: 99%
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