2006
DOI: 10.1007/s10711-006-9089-5
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Aspherical Kähler manifolds with solvable fundamental group

Abstract: Abstract. We survey recent developments which led to the proof of the Benson-Gordon conjecture on Kähler quotients of solvable Lie groups. In addition we prove that the Albanese morphism of a Kähler manifold which is a homotopy torus is a biholomorphic map. The latter result then implies the classification of compact aspherical Kähler manifolds with (virtually) solvable fundamental group up to biholomorphic equivalence. They are all biholomorphic to complex manifolds which are obtained as a quotient of C n by … Show more

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Cited by 27 publications
(31 citation statements)
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References 54 publications
(83 reference statements)
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“…For this, recall that a two-form ω ∈ 2 (R n ) * is called a polarisation for J (with respect to the lattice Z n ) if the following conditions are satisfied: 1. ω(J ·, J ·) = ω(·, ·), 2. g = ω(J ·, ·) is positive definite, 3. ω(Z n , Z n ) ⊆ Z.…”
Section: Theorem 11 the Group Is Kähler If And Only If It Admits A Cmentioning
confidence: 99%
“…For this, recall that a two-form ω ∈ 2 (R n ) * is called a polarisation for J (with respect to the lattice Z n ) if the following conditions are satisfied: 1. ω(J ·, J ·) = ω(·, ·), 2. g = ω(J ·, ·) is positive definite, 3. ω(Z n , Z n ) ⊆ Z.…”
Section: Theorem 11 the Group Is Kähler If And Only If It Admits A Cmentioning
confidence: 99%
“…Many results are known about Kähler Lie groups (see for instance [3]). Basic examples are flat Kähler Lie groups and solvable Kähler Lie groups acting simply transitively on a bounded domain in C n by biholomorphisms (see [17]).…”
Section: Proposition 64 a Cosymplectic Unimodular Lie Group Is Necesmentioning
confidence: 99%
“…In the present paper we will give a short proof of the fact that there are no Kähler structures on exotic tori. When this paper was written we have learned that this fact was known to algebraic geometers [BC,C1].…”
Section: Introductionmentioning
confidence: 99%
“…As a result of efforts of [A,AN,Ha,Ha1,TK] together with developments from algebraic geometry (see [BC,C1]) the final (affirmative) solution of this problem was recently achieved (See Section 3). To the authors knowledge, the final clean proof was given in [Ha,Ha1].…”
Section: Introductionmentioning
confidence: 99%
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