1995
DOI: 10.1305/ndjfl/1040136914
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Arithmetically Saturated Models of Arithmetic

Abstract: The paper presents an outline of the general theory of countable arithmetically saturated models of PA and some of its applications. We consider questions concerning the automorphism group of a countable recursively saturated model of PA. We prove new results concerning fixed point sets, open subgroups, and the cofinality of the automorphism group. We also prove that the standard system of a countable arithmetically saturated model of PA is determined by the lattice of its elementary substructures.is Th(N). Th… Show more

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Cited by 16 publications
(13 citation statements)
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“…1.4(iii)], although it is equivalent. One direction of this equivalence is given in [13,Theorem 1.7(1b)]; the other is easy to see. It is straightforward to see that every recursively saturated model is uniformly ω-lofty.…”
Section: Proposition 13mentioning
confidence: 96%
See 2 more Smart Citations
“…1.4(iii)], although it is equivalent. One direction of this equivalence is given in [13,Theorem 1.7(1b)]; the other is easy to see. It is straightforward to see that every recursively saturated model is uniformly ω-lofty.…”
Section: Proposition 13mentioning
confidence: 96%
“…This gave the first positive answer to the above question. A neater way, in which the use of the small index property is masked, that automorphism groups distinguish those models that are arithmetically saturated from the other countable recursively saturated ones was obtained the next year in [13,Coro. 3.9] (or see [15,Th.…”
mentioning
confidence: 99%
See 1 more Smart Citation
“…Earlier, in [9], it was proved that an arithmetically saturated M has an automorphism which moves every nondefinable element. It was asked in [9,Problem 4.5] if there is an automorphism g such that for any interstice Ω, either g(x) < x for all x ∈ Ω or g(x) > x for all x ∈ Ω. A consequence of Corollary 2.13 is that there is no such automorphism.…”
Section: Moving Intersticial Gapsmentioning
confidence: 99%
“…Two other proofs, perhaps a little more transparent than the original one, are in [9]. Suppose that g ∈ Aut(M) and a, b, d ∈ M are such that g(a) = a ≤ b < Gap(d).…”
Section: Introductionmentioning
confidence: 99%