“…During solidification processing, the exogenous particles from the grain refiner are in direct competition with the endogenous particles. If the endogenous particles have higher nucleation potency Al/TiB 2 S: fcc, a = 0.42112 [45] (111)[110]// 0.30372 0.29141 À4.22 N: hcp, a = 0.30372, c = 0.32368 [45] (0001)[11À20] Al/Al 3 Ti S: fcc a = 0.42112 (111)[110]//(112)[20À1] 0.29116 0.29141 0.09 N: tetragonal, a = 0.3883, c = 0.8679 [51] Al/ZrB 2 S: fcc a = 0.41212 (111)[110]//(0001)[11À20] 0.31690 0.29141 À8.75 N: hcp, a = 0.3883, c = 0.8679 [52] Mg/Zr S: hcp, a = 0.3265, c = 0.5308 [31] (0001)[11À20]//(0001)[11À20] 0.32431 0.32650 0.67 N: hcp, a = 0.32431, c = 0.5180 [53] Mg/Al 3 Zr S: hcp, a = 0.3265, c = 0.5308 (0001)[11À20]//(114)[110] 0.28553 0.32650 12.55 N: tetragonal, a = 0.4038, c = 1.7428 [54]c a The lattice parameters were calculated from room temperature data from JCPDS files and the coefficients of thermal expansion given in the relevant references. b The orientation relationship (OR) is obtained by assuming that the close packed direction on the close packed plane of the solid is parallel to its counterpart of the substrate.…”