2015
DOI: 10.1007/s12274-015-0868-x
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Anelasticity of twinned CuO nanowires

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Cited by 29 publications
(34 citation statements)
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“…Figure a is a pristine CuO−Pt NW with a total diameter of ∼32 nm (the diameter of CuO‐core NW is estimated to be 20 nm excluding 12 nm Pt‐shell) and Figure b is the corresponding enlarged view from the dashed white box. The NW can be bent to a maximum strain of 11.34% (Figure c), much higher than the results of uncoated CuO NWs (6.18%), which could be attributed to the protection of Pt‐shell . The strain of the CuO‐core is obtained based on the formula ϵ = D /2 ρ , where D denotes the diameter of the NW and ρ represents the curvature radius .…”
Section: Resultsmentioning
confidence: 90%
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“…Figure a is a pristine CuO−Pt NW with a total diameter of ∼32 nm (the diameter of CuO‐core NW is estimated to be 20 nm excluding 12 nm Pt‐shell) and Figure b is the corresponding enlarged view from the dashed white box. The NW can be bent to a maximum strain of 11.34% (Figure c), much higher than the results of uncoated CuO NWs (6.18%), which could be attributed to the protection of Pt‐shell . The strain of the CuO‐core is obtained based on the formula ϵ = D /2 ρ , where D denotes the diameter of the NW and ρ represents the curvature radius .…”
Section: Resultsmentioning
confidence: 90%
“…The NW can be bent to a maximum strain of 11.34% (Figure c), much higher than the results of uncoated CuO NWs (6.18%), which could be attributed to the protection of Pt‐shell . The strain of the CuO‐core is obtained based on the formula ϵ = D /2 ρ , where D denotes the diameter of the NW and ρ represents the curvature radius . Subsequently, the W tip was retracted as fast as possible to guarantee free recovery of the NW (see Movie 1 in the SI), and there exists a much higher residual strain (3.94%, as presented in Figure d and the corresponding enlarged view in Figure e) compared with that of CuO NW (0.51%) with similar diameter (17 nm) .…”
Section: Resultsmentioning
confidence: 99%
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“…[35] A study conducted by Huaping et al also concluded that the magnitude of anelasticity is highly dependent on the diameter metal nanowires as thicker surface amorphous layer would result in a higher driving force compared to that of a thinner one. [18] The largest room for error would be the measuring of the deflection of and dimensions of the nanowire. For the deflections, pixel distances would be the contribution.…”
Section: Figure 30: Experiments Conducted By Nc State University [35]mentioning
confidence: 99%