“…At equilibrium (i.e., at 100% breakthrough) C s = 16.2 mg per 2750 nL = 5801 mg L 21 and C m is the concentration of the original toluene standard, i.e., C m = 20 mg L 21 . Thus, log K = 2.47, which is in good agreement with the K value determined by equation (2), log K ow and log K determined from SPME (Table 2) 8,[11][12][13][14][15][16] reported for the same temperature. Recovery of the sorbed toluene by back extraction should yield 81 mg L 21 of toluene (16.2 mg per 100 mL of hexane, diluted 1 : 1 with IS solution).…”