2016
DOI: 10.1002/mma.4209
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An eco‐epidemic model for infectious keratoconjunctivitis caused by Mycoplasma conjunctivae in domestic and wild herbivores, with possible vaccination strategies

Abstract: In this paper, we propose an eco‐epidemiological predator–prey model, modeling the spread of infectious keratoconjunctivitis among domestic and wild ungulates, during the summer season, when they intermigle in high mountain pastures. The disease can be treated in the domestic animals, but for the wild herbivores, it leads to blindness, with consequent death. The model shows that the disease can lead infected herbivores or their predators to extinction, even if it does not affect the latter. Boundedness of solu… Show more

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Cited by 6 publications
(8 citation statements)
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“…Also microparasites may infect both the prey and the predator as tuberculosis bacteria in a lion-buffalo system [16] or rabies virus in a rabbit-fox system [66]. A system where the prey (small ruminants) does not pass on the parasite (a mycoplasma) to the predator (golden eagle, red fox) is considered in [1], but here density-dependent incidence is chosen, infected hosts can become susceptible again, and some susceptible hosts are vaccinated. The real world system closest to our model that we could find in the literature [6] has phytoplankton as prey/host, zooplankton as predator and a virus as microparasite.…”
Section: 2mentioning
confidence: 99%
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“…Also microparasites may infect both the prey and the predator as tuberculosis bacteria in a lion-buffalo system [16] or rabies virus in a rabbit-fox system [66]. A system where the prey (small ruminants) does not pass on the parasite (a mycoplasma) to the predator (golden eagle, red fox) is considered in [1], but here density-dependent incidence is chosen, infected hosts can become susceptible again, and some susceptible hosts are vaccinated. The real world system closest to our model that we could find in the literature [6] has phytoplankton as prey/host, zooplankton as predator and a virus as microparasite.…”
Section: 2mentioning
confidence: 99%
“…h(g(0)/µ) is equivalent to 1 < g(0)/µ. We choose S = K. Then the inequalities take the form µ h (1) < σ < g(0) h(g(0)/µ) , 0 < µ < g(0), µ h (0) < σ < µ + κg K 1 + γ h(1)(1 + κ) ,…”
Section: Remark 158mentioning
confidence: 99%
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