2023
DOI: 10.1007/s11005-023-01661-3
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Algorithms for minimal Picard–Fuchs operators of Feynman integrals

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Cited by 11 publications
(3 citation statements)
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“…[16], argues, on the basis of homology arguments, that all Feynman integrals must belong to a suitably generalised class of hypergeometric functions, an insight that was sharpened much more recently with the introduction of the Lee-Pomeransky representation [20] of Feynman integrals and the application of the GKZ theory of hypergeometric functions [21][22][23][24][25][26][27][28]. Regge further argues that such functions obey sets of (possibly) high-order differential equations, which he describes as 'a slight generalisation of the well-known Picard-Fuchs equations', also a recurrent theme [29].…”
Section: Jhep03(2024)096mentioning
confidence: 99%
“…[16], argues, on the basis of homology arguments, that all Feynman integrals must belong to a suitably generalised class of hypergeometric functions, an insight that was sharpened much more recently with the introduction of the Lee-Pomeransky representation [20] of Feynman integrals and the application of the GKZ theory of hypergeometric functions [21][22][23][24][25][26][27][28]. Regge further argues that such functions obey sets of (possibly) high-order differential equations, which he describes as 'a slight generalisation of the well-known Picard-Fuchs equations', also a recurrent theme [29].…”
Section: Jhep03(2024)096mentioning
confidence: 99%
“…[10][11][12][13][14][15][16][17] (see also refs. [18][19][20][21][22][23][24]). The ideals associated with Feynman integrals are holonomic and thus Feynman integrals are holonomic functions [25].…”
Section: Jhep10(2023)098mentioning
confidence: 99%
“…[29] so it would be interesting to construct canonical holonomic representations for these amplitudes and determine whether the resulting differential equations manifest a dependence on sub-amplitudes. (12,3,4,5,6), m 6 (1,23,4,5,6), m 6 (1,2,34,5,6), m 6 (1,2,3,45,6), m 6 (1, 2, 3, 4, 56), m 4 (1, 2, 3)m 5 (123,4,5,6), m 4 (2, 3, 4)m 5 (1,234,5,6), m 4 (3, 4, 5)m 5 (1,2,345,6), respectively, where we have used m 3 (w 1 , w 2 ) = 1.…”
Section: Jhep10(2023)098 4 Conclusionmentioning
confidence: 99%