2014
DOI: 10.1007/978-3-319-12691-3_5
|View full text |Cite
|
Sign up to set email alerts
|

Algorithms for Fair Partitioning of Convex Polygons

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
1
1
1

Citation Types

0
3
0

Year Published

2020
2020
2020
2020

Publication Types

Select...
2

Relationship

0
2

Authors

Journals

citations
Cited by 2 publications
(3 citation statements)
references
References 1 publication
0
3
0
Order By: Relevance
“…Even though Theorem 3.0.1 deals with fair partitions of measures, the proofs of Karasev, Hubard, and Aronov, and of Blagojević and Ziegler yield much more [KHA14,BZ14]. They were motivated by a question of Nandakumar and Ramana Rao, which asked if every polygon in the plane could be split into k convex parts of equal area and equal perimeter, for any positive integer k. If the polygon has n vertices, there are algorithms that find such a partition for k = 2 h in O((2n) h ) time [AD15].…”
Section: Convex Partitions Of R Dmentioning
confidence: 99%
“…Even though Theorem 3.0.1 deals with fair partitions of measures, the proofs of Karasev, Hubard, and Aronov, and of Blagojević and Ziegler yield much more [KHA14,BZ14]. They were motivated by a question of Nandakumar and Ramana Rao, which asked if every polygon in the plane could be split into k convex parts of equal area and equal perimeter, for any positive integer k. If the polygon has n vertices, there are algorithms that find such a partition for k = 2 h in O((2n) h ) time [AD15].…”
Section: Convex Partitions Of R Dmentioning
confidence: 99%
“…In these problems, the partition is not restricted to chords (or hyperplanes). Topological methods are used for existential results in this area, and very few algorithmic results are known [1]. Another related problem is the family of so-called cake cutting problems [15,31], in which an infinite straight line "knife" is used to cut a convex "cake" into (convex) pieces that represent a "fair" division into portions.…”
Section: Axis-parallel Lasersmentioning
confidence: 99%
“…, n, if τ (x i ) = true, then place a horizontal laser at y = 3(i − 1) + 1 (along the bottom corridor touching room for x i ), otherwise at y = 3(i − 1) + 2 (along the top corridor touching room for x i ). These lasers split each variable room into two rectangles of area 1 2 and 3 2 . For j = 1, .…”
Section: Hardness In Polygons With Holesmentioning
confidence: 99%