2007
DOI: 10.4064/aa130-1-3
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Algebraic relations for reciprocal sums of Fibonacci numbers

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Cited by 26 publications
(25 citation statements)
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“…Substituting the expansion z −2 + ∞ j=0 c j (k)z 2j of ns 2 (k, z) into these equations, we can determine the coefficients c j (k) (see [4,Lemma 2] and the recursive relation in it). The relation ns 2 (1, z) = coth 2 z immediately follows from the fact that u = ns 2 (1, z) satisfies the equation (u ) 2 = 4u(u − 1) 2 admitting the general solution coth 2 (z − z 0 ).…”
Section: Lemmamentioning
confidence: 99%
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“…Substituting the expansion z −2 + ∞ j=0 c j (k)z 2j of ns 2 (k, z) into these equations, we can determine the coefficients c j (k) (see [4,Lemma 2] and the recursive relation in it). The relation ns 2 (1, z) = coth 2 z immediately follows from the fact that u = ns 2 (1, z) satisfies the equation (u ) 2 = 4u(u − 1) 2 admitting the general solution coth 2 (z − z 0 ).…”
Section: Lemmamentioning
confidence: 99%
“…where Table 1(i)], [4]). The series A 2j+1 (β(k) 2 ) are generated by Tables 1(i)], [9], [11, p. 535]), namely…”
Section: Proof Of Theorem 1 Recall Thatmentioning
confidence: 99%
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“…3). In the preceding paper [2] we proved that the numbers ζ F (2), ζ F (4), ζ F (6) are algebraically independent and for any integer s ≥ 4 ζ F (2s) − 5 s−2 r s ζ F (4) ∈ Q(u, v), u := ζ F (2), v := ζ F (6) with some r s ∈ Q (r s = 0 if and only if s is odd), where the rational function of u and v is explicit; for example,…”
Section: Introductionmentioning
confidence: 97%