1983
DOI: 10.1080/00927878308822902
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Algebraic function fields with solvable automorphism group in characteristic p

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Cited by 4 publications
(4 citation statements)
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“…The constant field of M 1 is k 1 and M = M 1 N . This implies that g M = g M 1 , and by (3) it follows that g M 1 > C. 2 PROPOSITION 4.2. Suppose that K /k is a function field such that K /k(y) is a finite extension, where K 0 is the separable closure of k(y) in K .…”
Section: K(y)mentioning
confidence: 85%
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“…The constant field of M 1 is k 1 and M = M 1 N . This implies that g M = g M 1 , and by (3) it follows that g M 1 > C. 2 PROPOSITION 4.2. Suppose that K /k is a function field such that K /k(y) is a finite extension, where K 0 is the separable closure of k(y) in K .…”
Section: K(y)mentioning
confidence: 85%
“…Madden and Valentini [6] proved that every finite group can be realized as the full automorphism group of an algebraic function field K /k. D'Mello and Madan [3] established the theorem of Greenberg in the case where G is a solvable group G and K = k(x) is a rational function field.…”
Section: Introductionmentioning
confidence: 99%
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