1945
DOI: 10.1525/aa.1945.47.4.02a00140
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AFRICA AND ASIA: Kota Texts. M. B. EMENEAU

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Cited by 4 publications
(9 citation statements)
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“…The force of the potential (18) is a super long-range force and will play a dominate role in a very large cosmic scale. The gauge field theory based on the taiji gauge invariant Lagrangian (11) suggests that the accelerated cosmic expansion could be understood in terms of the cosmic force produced by the taiji gauge field in (12).…”
Section: Linear Potentials Between Baryon Galaxiesmentioning
confidence: 99%
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“…The force of the potential (18) is a super long-range force and will play a dominate role in a very large cosmic scale. The gauge field theory based on the taiji gauge invariant Lagrangian (11) suggests that the accelerated cosmic expansion could be understood in terms of the cosmic force produced by the taiji gauge field in (12).…”
Section: Linear Potentials Between Baryon Galaxiesmentioning
confidence: 99%
“…For decades, it has been thought that higher-order field equations involve ghost states with non-definite energy or non-positive norm, which will upset unitarity of the theory. However, it was shown recently that this is not necessarily so, [10,11,12] and thereby one could apply fourth-order field equations to discuss physical phenomena. Bender and Mannheim proved a no-ghost theorem [10] for the fourth-order derivative Pais-Uhlenbeck oscillator model.…”
Section: Introductionmentioning
confidence: 99%
“…This calculation makes use of the fact that the non-Hermiticity effects in this model diminish for energy states with larger spectral label N. More specifically it is ζ/N 2 that plays the role of the perturbation parameter. More recently, Bender and Tan [12] performed a more conventional perturbative calculation of a metric operator taking ζ as the perturbation parameter. This is the metric operator η + that is associated with the CPT -inner product (·, ·) CPT , [26].…”
Section: Series Expansion For η(X Y)mentioning
confidence: 99%
“…Expressing η + in its exponential form, η + = e −Q , and noting that Bender and Tan set = 2m = L/π = 1, take ǫ = −ζ for the coupling constant, and use "ε(x)" for " sign(x)", we can summarize their principal result (Eq. (11) of [12]) as…”
Section: Series Expansion For η(X Y)mentioning
confidence: 99%
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