2019
DOI: 10.1214/19-aap1477
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Affine Volterra processes

Abstract: We introduce affine Volterra processes, defined as solutions of certain stochastic convolution equations with affine coefficients. Classical affine diffusions constitute a special case, but affine Volterra processes are neither semimartingales, nor Markov processes in general. We provide explicit exponential-affine representations of the Fourier-Laplace functional in terms of the solution of an associated system of deterministic integral equations, extending well-known formulas for classical affine diffusions.… Show more

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Cited by 103 publications
(238 citation statements)
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“…So fast pricing of European options is possible, see [6,19]. In addition derivatives hedging is fully understood as shown in [15,16], see also [1,9].…”
Section: Rough Volatility and The Zumbach Effectmentioning
confidence: 99%
“…So fast pricing of European options is possible, see [6,19]. In addition derivatives hedging is fully understood as shown in [15,16], see also [1,9].…”
Section: Rough Volatility and The Zumbach Effectmentioning
confidence: 99%
“…In fact, this condition alone ensures that the process V is an affine Volterra process, and by [2, Theorem 3.3], Assumption 2.1(i) ensures that the SDE for V admits a continuous weak solution, with sup t≥0 E[|V t | p ] finite for all p ≥ 2. This in particular implies [2,Theorem 4.3] that, under suitable integrability conditions,…”
Section: 1mentioning
confidence: 88%
“…The form of the kernel K ensures that the variance process is stationary. We borrow Condition (ii) from [2] so that, in the purely stochastic volatility case L(·, ·) ≡ 1, taking ς(v) = √ v, we are exactly in the setting of an affine Volterra system (log(S), V ). In fact, this condition alone ensures that the process V is an affine Volterra process, and by [2, Theorem 3.3], Assumption 2.1(i) ensures that the SDE for V admits a continuous weak solution, with sup t≥0 E[|V t | p ] finite for all p ≥ 2.…”
Section: 1mentioning
confidence: 99%
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“…Note that this is not of standard Volterra form, as e.g. in [2], since Y (t, s) or E[X t |F s ] respectively cannot be expressed as a function of V t . By moving to a Brownian field analogous to (1.4) it could however be expressed as a path functional of (V s ) s≤t .…”
Section: )mentioning
confidence: 99%