1973
DOI: 10.2172/4449786
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Adjoining appropriate singular elements to transport theory computations

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Cited by 3 publications
(5 citation statements)
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“…In particular, to test our bounds (2.12), we have applied the «-point Gauss-Laguerre formula to the following integral: (3.3) h= / e-xEx(\x-y\)xbdx, Jo where Ex(t) denotes the exponential integral (see [1]). Their kernels satisfy condition (2.14) with a = 0 and appear in certain well-known Wiener-Hopf integral equations (see [2,13,22]). License or copyright restrictions may apply to redistribution; see http://www.ams.org/journal-terms-of-use…”
Section: Numerical Resultsmentioning
confidence: 99%
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“…In particular, to test our bounds (2.12), we have applied the «-point Gauss-Laguerre formula to the following integral: (3.3) h= / e-xEx(\x-y\)xbdx, Jo where Ex(t) denotes the exponential integral (see [1]). Their kernels satisfy condition (2.14) with a = 0 and appear in certain well-known Wiener-Hopf integral equations (see [2,13,22]). License or copyright restrictions may apply to redistribution; see http://www.ams.org/journal-terms-of-use…”
Section: Numerical Resultsmentioning
confidence: 99%
“…Finally, we consider one further application of the product rule used in the last example. We use it to construct a Nyström interpolant for the following case of the well-known linear transport equation (see [2,13]): (3.21) u(y) -± jH Ex(\x -y\)u(x) dx = \ , whose solution at x = 0 assumes the known value u(0) = ^ .…”
Section: Numerical Resultsmentioning
confidence: 99%
See 1 more Smart Citation
“…In particular, to test our bounds (2.12), we have applied the «-point Gauss-Laguerre formula to the following integral: (3.3) h= / e-xEx(\x-y\)xbdx, Jo where Ex(t) denotes the exponential integral (see [1]). Their kernels satisfy condition (2.14) with a = 0 and appear in certain well-known Wiener-Hopf integral equations (see [2,13,22]). We recall (see [10]) that the coefficients wni(y) of (2.13) can be represented as follows: We consider first the case K(x, y) = e~\x~y\.…”
Section: Numerical Resultsmentioning
confidence: 99%
“…Finally, we consider one further application of the product rule used in the last example. We use it to construct a Nyström interpolant for the following case of the well-known linear transport equation (see [2,13]): (3.21) u(y) -± jH Ex(\x -y\)u(x) dx = \ , whose solution at x = 0 assumes the known value u(0) = ^ . Since it is known (see [13]) that lim;c_,00 u(x) = 1 and u(x) -1 = o(e~ßX) as x -> oo, for any 0 < p < p*, p* = 0.957504, we set u(x) = u(x) -1 and rewrite (3.21) in the following form: We recall that ß e Cq°[0, oo) and, furthermore, as x -> 0 the solution u{x) behaves like c + xb for any 0 < b < 1 (see [13]).…”
Section: )mentioning
confidence: 99%