2011
DOI: 10.1007/s00013-011-0277-7
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Additional results to a theorem of Eisenträger and Everest

Abstract: Revisiting a recent result of Eisenträger and Everest who proved that Hilbert's tenth problem is undecidable over certain subrings of Q, two additional theorems are proved. The theorems show that we can specify certain conditions for the sets of primes which define these rings. Thus, the freedom we have when choosing these rings is further illustrated.Mathematics Subject Classification (2010). 11G05, 11U05.

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Cited by 5 publications
(5 citation statements)
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“…In this paper we generalize the results of [16], [6] and [14] to prove the following theorems: Theorem 1.7. Let K be a number field, and assume there is an elliptic curve defined over K with K-rank equal to 1.…”
Section: Introductionmentioning
confidence: 88%
See 1 more Smart Citation
“…In this paper we generalize the results of [16], [6] and [14] to prove the following theorems: Theorem 1.7. Let K be a number field, and assume there is an elliptic curve defined over K with K-rank equal to 1.…”
Section: Introductionmentioning
confidence: 88%
“…More specifically, they proved that the rational primes can be partitioned into two disjoint sets S 1 , S 2 such that Hilbert's Tenth Problem is undecidable over both O K,S 1 and O K,S 2 . These results were improved by Perlega in [14] to show that the two sets can be of arbitrary computable densities.…”
Section: Introductionmentioning
confidence: 98%
“…subrings where infinitely many, though not all, primes are inverted). See [20], [23], [7], [17], [8] and [38].…”
Section: Using Elliptic Curves With Finitely Generated Groupsmentioning
confidence: 99%
“…There exist computable sets S of natural density zero and of natural density one such that HTP(Z[S −1 ]) is undecidable. This remarkable paper was followed by generalizations in [ES09], [Per11], and [EES11]. However, no attempt has been made so far in trying to compare HTP(Z[S −1 ]) to HTP(Q).…”
Section: Theorem ([Poo03]mentioning
confidence: 99%
“…This remarkable paper was followed by generalizations in [ES09], [Per11], and [EES11]. However, no attempt has been made so far in trying to compare HTP(Z[S −1 ]) to HTP(Q).…”
Section: Introductionmentioning
confidence: 99%