“…For three of these materials (Zr, ZrO 2 and MoO 2 ), these are the absolute numbers from a calculation of: where N , the areal density of atoms in the area exposed to the beam, is calculated from nt , where n is the number of atoms per unit volume (based on detailed knowledge of the crystal structure) and t is the sample thickness. This is obtained from the low loss using a calculated value of the mean free path for inelastic scattering, λ [ 11 , 12 ]. The Mo sample was a sputtered nanocrystalline film – if it is assumed to have the structure of bulk bcc Mo, then this would have a density of 10.22 g cm −3 .…”