“Absolute Measurements in Electricity and Magnetism.”

Gray, Andrew

doi:10.1259/jrs.1922.0042

Cited by 7 publications

(14 citation statements)

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“…any two of the fil aments is given by Neumann's formula, (2) The distance r is between two elements of length dl 1 and dl 2 which are along two filaments having total length l1 and l2' resp ectively. For dimensions in centimeters, M12 is in microhenrys.…”

Section: Mutual Inductance Calculationsmentioning

confidence: 99%

“…Using (2) and (3), the mutual inductance between any two conductors having constant crosssectional areas and uniform (but not necessarily equ al) current densities may be evaluated. Results obtained from (2) and (3) are quite useful even though the current den sities are not uniform. In many cases, the conductors m ay be subdivided into elements small enough so that each element may b e considered as having a uniform cmrent density.…”

Section: Mutual Inductance Calculationsmentioning

confidence: 99%

“…The mutual inductances between th e smaller elements are then properly summed to get the total mu tual inductance. R esults from (2) and (3) are also useful when the cross-section al area of a conductm is not uniform along its length . In this case th e conductor is subdivided into sections, each of which has a constant cross-sectional area along its length.…”

Section: Mutual Inductance Calculationsmentioning

confidence: 99%

“…If exact values of inductance are not required, the equivalent self-inductance often may be calculated easier using geometric-mean-distances [1][2][3][4][5][6][7] …”

Section: -4 38----<65mentioning

confidence: 99%

“…A number of approximate equations exist for calculatin g the inductance of rectangular ~onductors [1][2][3][4][5]. 1 The usual method is to calculate the mutual inductance between two filaments spaced a distance apart equal to the geometric-mean-distance [6] of the conductor or conductors.…”

Section: Introductionmentioning

confidence: 99%

See 4 more Smart Citations

Exact inductance equations for rectangular conductors with applications to more complicated geometries

Hoer¹,

Love²

1965

J. RES. NATL. BUR. STAN. SECT. C. ENG. INSTR.

271

130

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Exact eq uations a re given for t he calculation of t he self-inductance of rcctangular conductors a nd of t he lIlutual inducta nce between combinations of parallel fil a mcnts, thin tapcs and rectangular conductors. A general procedure is also given for calculating the sclfinductance of complicated geometri es by dividing the gcometry into simple elcm ents whose inductances can be calculated. This general proccdure is valid for conductors having nonuniform, as well as uniform current dcnsities.

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Section: Mutual Inductance Calculationsmentioning

confidence: 99%

Section: Mutual Inductance Calculationsmentioning

confidence: 99%

Section: Mutual Inductance Calculationsmentioning

confidence: 99%

“…If exact values of inductance are not required, the equivalent self-inductance often may be calculated easier using geometric-mean-distances [1][2][3][4][5][6][7] …”

Section: -4 38----<65mentioning

confidence: 99%

Section: Introductionmentioning

confidence: 99%

See 3 more Smart Citations

Exact inductance equations for rectangular conductors with applications to more complicated geometries

Hoer¹,

Love²

1965

J. RES. NATL. BUR. STAN. SECT. C. ENG. INSTR.

271

130

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Thermodynamic equilibrium in dielectric fluids

Barletta¹,

Zanchini²

1994

Il Nuovo Cimento D

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A rigorous deduction of the thermodynamic-equilibrium condition is provided for a homogeneous, uncharged and linear dielectric fluid contained in an electrostatic field. Contrary to the previous ones, this deduction does not postulate the existence of a mechanical stress tensor and of a body force density in the polarized fluid. Then, the equilibrium condition is employed to obtain the mass density distribution of the fluid and to present a correct proof of the well-known formula for the attractive force between the plates of a plane-parallel capacitor immersed in the fluid.

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Calculation of hysteresis losses in hard superconductors carrying ac: isolated conductors and edges of thin sheets

Norris¹

1970

J. Phys. D: Appl. Phys.

1,078

658

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Two methods of calculating hysteresis losses in hard superconductors are described. The London model is assumed in which the critical current density is taken independent of magnetic field. Losses in isolated wires of different cross section are considered but it is found that losses for solid wires vary by at most a factor of 3 for different shaped wires of the same current-carrying capacity. The loss at saturation current is usually 0.4-0.6 I c z p~/ n. Losses at theedges of thin sheets are also calculated and a fourth-power dependence on current (for low current) is found. Three systems are examined: a slit parallel to the current in a wide sheet (L e-poj2g2r3F4/24), one pair of the edges of two wide strips set back-to-back and carrying antiparallel currents (Le 2 ponj2s2F4/6) and a long thin wall parallel to the current flow on a wide sheet (L c~p~. r r 3 j 2 a 2 F ' i / 3). Le is the loss per cycle per unit length, F is the current peak as a fraction of saturation current, g the width of the slit, s the spacing of strips, a the height of the asperity and j the critical current density per unit width. All in MKS units.

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“Absolute Measurements in Electricity and Magnetism.”

Cited by 7 publications

References 0 publications

Exact inductance equations for rectangular conductors with applications to more complicated geometries

Exact inductance equations for rectangular conductors with applications to more complicated geometries

Thermodynamic equilibrium in dielectric fluids

Calculation of hysteresis losses in hard superconductors carrying ac: isolated conductors and edges of thin sheets

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