“…Proof. First, observe that Dom(T ) contains all finite sequences and hence it is dense in 2 . Next, since {λ n } ∞ n=1 is a sequence of real numbers, T is clearly symmetric and thus T * is an extension of T .…”
Section: Preliminariesmentioning
confidence: 99%
“…is a bounded functional. This functional has a unique bounded extension to 2 and, therefore, by the Riesz representation theorem, it can be represented by a unique c ∈ 2 . That is,…”
Section: Preliminariesmentioning
confidence: 99%
“…The solution of the example above illustrates the construction used in [2] to prove the following theorem.…”
Section: Identifying the Set Of Matricesmentioning
confidence: 99%
“…This inverse spectrum problem was considered in [2] under the assumption that the given spectrum Λ is compact. Since the spectrum of any bounded operator is a compact subset of the complex plane, the main result of [2] is in this sense optimal for bounded operators.…”
Section: Introductionmentioning
confidence: 99%
“…This inverse spectrum problem was considered in [2] under the assumption that the given spectrum Λ is compact. Since the spectrum of any bounded operator is a compact subset of the complex plane, the main result of [2] is in this sense optimal for bounded operators. Additionally, because the spectrum of any unbounded operator is a closed subset of the complex plane (see, for instance, [5,Proposition 2.6]), it is natural to ask whether one can replace the compactness assumption of Λ by closedness.…”
Given an infinite graph G on countably many vertices, and a closed, infinite set Λ of real numbers, we prove the existence of an unbounded self-adjoint operator whose graph is G and whose spectrum is Λ.
“…Proof. First, observe that Dom(T ) contains all finite sequences and hence it is dense in 2 . Next, since {λ n } ∞ n=1 is a sequence of real numbers, T is clearly symmetric and thus T * is an extension of T .…”
Section: Preliminariesmentioning
confidence: 99%
“…is a bounded functional. This functional has a unique bounded extension to 2 and, therefore, by the Riesz representation theorem, it can be represented by a unique c ∈ 2 . That is,…”
Section: Preliminariesmentioning
confidence: 99%
“…The solution of the example above illustrates the construction used in [2] to prove the following theorem.…”
Section: Identifying the Set Of Matricesmentioning
confidence: 99%
“…This inverse spectrum problem was considered in [2] under the assumption that the given spectrum Λ is compact. Since the spectrum of any bounded operator is a compact subset of the complex plane, the main result of [2] is in this sense optimal for bounded operators.…”
Section: Introductionmentioning
confidence: 99%
“…This inverse spectrum problem was considered in [2] under the assumption that the given spectrum Λ is compact. Since the spectrum of any bounded operator is a compact subset of the complex plane, the main result of [2] is in this sense optimal for bounded operators. Additionally, because the spectrum of any unbounded operator is a closed subset of the complex plane (see, for instance, [5,Proposition 2.6]), it is natural to ask whether one can replace the compactness assumption of Λ by closedness.…”
Given an infinite graph G on countably many vertices, and a closed, infinite set Λ of real numbers, we prove the existence of an unbounded self-adjoint operator whose graph is G and whose spectrum is Λ.
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